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3 years ago

Solve for x: 1 < x + 3 < 4

Mathematics

1 answer:

MrRa [10]3 years ago

4 0

It’s clearly number 2. 3 and 4 don’t have a 4 so it leaves 1 and 2 1 has gt so that’s wrong so it’s 2 because it has lt

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What is m = 2/3; (6, 1) in slope intercept form? :)

Marina86 [1]

Answer:

y = 2/3x - 3

Step-by-step explanation:

First let's look at what slope-intercept form is.

y = mx + b

m is the slope, which in this case is 2/3

b is the y-intercept, which we will find later.

Now that we have identified the parts of the equation, let's plug in what we know. Use the point given for your x and y values.

y = mx + b

1 = 2/3(6) + b

Let's simplify this to find b.

[multiply] 1 = 4 + b

[subtract 4]

-3 = b

We now have our b-value, which is also our y-intercept. Plug in this value into the standard slope-intercept equation.

y = 2/3x - 3

This is your equation.

Check this by plugging in the point again.

1 = 2/3(6) - 3

[multiply] 1 = 4 - 3

[subtract]

1 = 1

This expression is true; therefore, your answer is correct.

Hope this helps!

7 0

3 years ago

The formula for interest is I=Prt. Describe what these letters stand for. Is the formula the same if you are charged interest on

prisoha [69]

Answer:

I stand for interest

P stand for principle

R stand for rate

T stand for time

There are the same.

7 0

3 years ago

Which four inequalities can be used to find the solution to this absolute value inequality?

natita [175]

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the inequality:

3 ≤ |x + 2| ≤ 6

Hence:

x + 2 ≤ 6, -(x + 2) ≤ 6, 3 ≤ x + 2 and 3 ≤ -(x + 2)

This gives:

x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

The four inequalities that can be used to find the solution of 3 ≤ |x + 2| ≤ 6 is x + 2 ≤ 6, x + 2 ≥ -6, x + 2 ≥ 3 and x + 2 ≤ -3

Find out more on equation at: brainly.com/question/2972832

#SPJ1

6 0

2 years ago

Solve the inequality:

steposvetlana [31]

Answer:

x >_ 1

Step-by-step explanation:

Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!

(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)

8 + 4x >_ 12

-8 -8

4x >_ 4

/4 /4

x >_ 1

6 0

3 years ago

a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was

Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em> $\bar X$ <em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = population mean hours spent studying = 25 hours

$\sigma$ = standard deviation = 15 hours

n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < $\bar X$ < 30 hours)

P(29 hours < $\bar X$ < 30 hours) = P( $\bar X$ < 30 hours) - P( $\bar X$ $\leq$ 29 hours)

P( $\bar X$ < 30 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ < $\frac{ 30-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z < 2) = 0.97725

P( $\bar X$ $\leq$ 29 hours) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }$ $\leq$ $\frac{ 29-25}{\frac{15}{\sqrt{36} } }} }$ ) = P(Z $\leq$ 1.60) = 0.94520

<em>So, in the z table the P(Z </em> $\leq$ <em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < $\bar X$ < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0

3 years ago