3 years ago

Item 4 Evaluate 8x−y2−3 when x=−1/4 and y=3 .

Mathematics

2 answers:

iren2701 [21]3 years ago

8 0

8(-1/4)-(3)2-3=-2-6-3=-11

Semmy [17]3 years ago

8 0

Answer:

-14

Step-by-step explanation:

8x-y^2-3

8(-1/4)-(3)^2-3

-8/4-3*3-3

-2-9-3

-11-3

-14

You might be interested in

Blake makes $275 per week but 20 percent is withheld from his paycheck for taxes. How much does Blake bring home each week?

rjkz [21]

275×0.20 equals $55 withheld. 275-55=220. He brings home $220 each week

4 0

3 years ago

Read 2 more answers

25 pts plz help!!!!!!!!!!!

alexdok [17]

Which part needs answering ?

3 0

2 years ago

Read 2 more answers

Eleanor scores 680 on the mathematics part of the SAT. The distribution of SAT math scores in recent years has been Normal with

Katen [24]

Answer:

Elanor's standardized score is 1.19
Gerald's standardized score is 0.72
Elanor has higher score

Step-by-step explanation:

To compare Elanor's and Gerald's math scores, we need to standardize them and calculate their z-scores.

z score can be calculated using the formula

z= $\frac{X-M}{s}$ where

X is the student's score

M is the mean score of the exam

s is the standard deviation of the exam

Elanor's standardized score is:

z(e) = $\frac{680-554}{106}$ ≈ 1.19

Gerald's standardized score is:

z(g)= $\frac{27-24.7}{3.2}$ ≈ 0.72

Since z(e) > z(g), Elanor has higher score

6 0

3 years ago

What is the y-intercept of the equation of the line that is perpendicular to the line y =

igor_vitrenko [27]

Answer:

y=-5/3x+20

Step-by-step explanation:

Let the equation of the required line be represented as $y=mx+c$

This line is perpendicular to the line $y=\frac{3}{5}x+10$

$=>m*\frac{3}{5}=-1$

$=>m=\frac{-5}{3}$

So the equation of the required line becomes $y=\frac{-5}{3}x+c$

This line passes through the point (15.-5)

$-5=\frac{-5}{3}*15+c$

$=>c=20$

So the equation of the required line is $y=\frac{-5}{3}x+20$

Among the given options, option 4 is the correct one.

3 0

2 years ago

The coordinates of a point on a coordinate grid are (−2, 6). The point is reflected across the x-axis to obtain a new point. The

cluponka [151]

The reflection across the x-axis only change the signal of the y coordinate. Hence, the new point is $P'(-2,-6)$ .

4 0

3 years ago