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lina2011 [118]
3 years ago
5

I need help with the question above

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0
2a/5b = 6

(2a-5b)/5b could be written as: (2a/5b) -(5b/5b)

Repace by its equivalent value (6) -(1) = 5

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Question 5 (25. pts)
Pie

Answer:

No matter where the center of rotation is located on the coordinate plane, each point in the preimage is the same distance from the point of rotation as its corresponding point in the rotated images. This distance is not affected by changing the location of P. Although this investigation covered vertices only, it's clear that any point on a shape or figure will be affected similarly.

Step-by-step explanation:

7 0
3 years ago
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12 chocolate bars for $22 or 20 chocolate bars for $33 use unit rate to determine the better buy.
jekas [21]
12c=22
6c=11
c=1 5/6
20c=33
c= 1 13/20
5/6 is about .83
13/20 is .65
12 chocolate bars for $22 is about $1.83 each
20 chocolate bars for $33 is $1.65 each

The 20 chocolate bars for $33 dollars has a better unit rate and is a better buy.
6 0
3 years ago
What is the argument of -5\sqrt{3}+ 5i?
Shtirlitz [24]

Answer:

150 degrees

Step-by-step explanation:

Graphing the complex number we see the angle terminates in the second quadrant. This means the argument, the angle, will be between 90 degrees and 180 degrees.

So if we create a right triangle with that point after graphing it. We see the height of that triangle is 5 because that is the imaginary part. The base of that triangle has length 5\sqrt{3}. The problem is this doesn't give us any part of the angle we want, but it does give us the complementary of the part of the angle that is in second quadrant.

Let's find the complementary angle.

So the opposite side of the complementary angle is 5.

The adjacent side of the complementary angle is 5\sqrt{3}.

\tan(\theta)=\frac{5}{5\sqrt{3}}

\tan(\theta)=\frac{1}{\sqrt{3}}

\theta=\tan^{-1}(\frac{1}{\sqrt{3}})

\theta=30

So 90-30=60.

The answer therefore 60+90=150.

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3 years ago
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3/4 divided by 3/12 is 3 
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The elevation of city A is 80 feet below sea level; the elevation of city C is 16 feet below sea level. The elevation of city D
Ipatiy [6.2K]
Part A: -16 divided by 1/2 =D
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3 years ago
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