We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:

Where
represents the number of objects/people in the set and
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set


Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get

Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
Where's the table?
Step-by-step explanation:
Answer:
x= 35
Step-by-step explanation:
supposing we are finding x, we know that the line in the middle is the dimeter. so we know its a semicircle with an arc of 180 degrees. 180-110=70 divide that by two to get x which is 35.
Answer:b
Omnivore and predator
Step-by-step explanation:
Answer:
b+a+09=097
Step-by-step explanation:
welcome