Answer:the nth term of the sequence, Tn= -3n +12
Step-by-step explanation:
The nth term of an arithmetic progression is given as
Tn= a+ (n-1) d
where a= first term
and d = common difference
In this sequence, 9, 6 ,3 ,0, -3, -6 we can see that the number is decreasing by 3
The first term, a= 9
and common difference, d = -3
using our formulae
Tn= a+ (n-1) d
Tn= 9 + ( n-1) -3
Tn=9- 3n+ 3
Tn= -3n +12
Answer:
Let's call:
f = price of 1 cup of dried fruit
a = price of 1 cup of almonds
In order to build the linear system, you need to consider that the total price of a bag is given by the sum of the price of cups times the number of cups in each bag, therefore:
Solve for a in first equation:
a = (6 - 3f) / 4
Then substitute in the second equation:
41/2 f + 6 · (6 - 3f) / 4 = 9
41/2 f + 9 - 9/2 f = 9
16 f = 0
f = 0
Now, substitute this value in the formula found for a:
a = (6 - 3·0) / 4
= 3/2 = 1.5
Hence, the cups of dried fruit are free and 1 cup of almond costs 1.5$
Step-by-step explanation:
Answer: 81%
Step-by-step explanation:
From the question, we are informed that a student received the following test scores: 71%, 89%, 72%,
84% and 83% in 5 tests and the student wants to maintain an average of 80%.
The lowest score/grade they can receive on the next test to maintain at least an 80% average first thus:
First, to make it easy we can remove the percent sign. Then we multiply 80 by 6 since we're calculating for 6 tests scores. This will be:
= 80 × 6
= 480
We then add all the 5 test scores. This will be:
= 71 + 89 + 72 + 84 + 83
= 399
We then subtract the values gotten. This will be:
= 480 - 399
= 81
This means the student must get at least 81%
113.25 because the middle ground of 1 - 150 students is 75 and then 1+150=151 2+149+151 but instead of doing that again and again just multiply the lowest number and the highest number by the middle ground
Answer:
Unit 4- Expressions and Equations: In this unit, students build on their knowledge from unit 2, where they extended the laws of exponents to rational exponents. Students apply this new understanding of number and strengthen their ability to see structure in and create quadratic and exponential expressions.
