0.118 m is the distance between the two protons.
Mass of proton = 1.6726 × 10⁻²⁷ kg
Weight of proton= 1.6726 × 10⁻²⁷ x 9.81 N
= 1.6408 × 10⁻²⁶ N
Charge of proton = 1.602 × 10⁻²⁹ C
The force between two protons = kq²/r² where, K is a proportionality
constant, q is a charge of proton and
r is the distance between two protons.
= 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
To calculate distance :
Weight of proton= Force between protons
⇒ 1.6408 × 10⁻²⁶ N = 9 × 10⁹ × (1.602×10⁻¹⁹)²/r²
⇒ r = 0.118m
Therefore, 0.118 m is the distance between the two protons.
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Answer:
The series A test tube has some left amount of glucose left in it.
Explanation:
Let's assume that a fixed amount of glucose is synthesized, for the fixed quantity the bacteria produced in A and B be x and y respectively,
Therefore, the condition on x and y is, y > x as the no. of bacteria present in B is greater.
As a result B would require a greater amount of energy for its functioning, these energy would be derived from the already fixed amount of glucose present.
A test tube would also require the energy for its x number of bacteria, but it is less than that of B.
Therefore, there would be some unused glucose left in Test Tube Series A which has unused energy.
Answer:
a.
Explanation:
a
The property of air mass include
1) it must be large.
2) it must have relatively uniform properties.
3)it must travel as a recognizable entity.
It must have a warm front at its leading edge, is not necessarily a property of an air mass because Not all air masses have a warm front at their leading edge. There are five types of air masses and different types of the front can be developed.
