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Inessa05 [86]
3 years ago
15

Ocean waves travel in to the beach at an average velocity of 2.5 m s . If these waves come in 4 seconds apart, what is the avera

ge distance between the wave peaks, considering the formula V= d t ?
Physics
2 answers:
Kryger [21]3 years ago
8 0

Answer : Average distance is 10 m.

Explanation :

It is given that,

Average velocity of the wave, v=2.5\ m/s

Time, T=4\ s

So, frequency \nu=\dfrac{1}{T}=\dfrac{1}{4}\ Hz

We know that the average distance between the wave peaks is called as wavelength.

The relation between the wavelength, frequency and the time period is :

\lambda=\dfrac{v}{\nu}

\lambda=\dfrac{2.5\ m/s}{\dfrac{1}{4\ s}}

\lambda=10\ m

So, the average distance between the wave peaks is 10 m.

cestrela7 [59]3 years ago
6 0

2.5 \times 4
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Answer:

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Explanation:

Given;

initial angular velocity, \omega_i = 10 rad/s

final angular velocity, \omega_f = 25 rad/s

time of motion, t = 10 s

The angular acceleration of the car is calculated as follows;

a_r = \frac{\omega_f - \omega_i }{t} \\\\a_r = \frac{25-10}{10} = 1.5 \ rad/s^2

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v= \frac{d}{t}
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d = distance traveled
t = time/period

First you need to consider that the orbit is circular. To get the measurement or the distance going around Earth, you will need to get the circumference of the path. 

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Where:
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