All categories

3 years ago

Which of the following is NOT NECESSARILY a property of an air mass?

Physics

1 answer:

lilavasa [31]3 years ago

4 0

Answer:

Explanation:

The property of air mass include

1) it must be large.

2) it must have relatively uniform properties.

3)it must travel as a recognizable entity.

It must have a warm front at its leading edge, is not necessarily a property of an air mass because Not all air masses have a warm front at their leading edge. There are five types of air masses and different types of the front can be developed.

You might be interested in

An unwary football player collides with a padded goalpost while running at a velocity of 9.50 m/s and comes to a full stop after

Amanda [17]

Answer:

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

Explanation:

Given:

Initial velocity of the player (u) = 9.50 m/s

Final velocity of the player (v) = 0 m/s (Comes to a stop)

Displacement of the player (S) = 0.250 m

We know that, using equation of motion relating displacement (S), acceleration (a), initial velocity (u) and final velocity (v), we have:

$v^2=u^2+2aS$

Expressing in terms of 'a', we get:

$a=\frac{v^2-u^2}{2S}$

Plug in the given values and solve for 'a'. This gives,

$a=\frac{0-9.50^2}{2\times 0.250}\\\\a=\frac{-90.25}{0.5}=-180.5\ m/s^2$

Therefore, the acceleration of the player is -180.5 m/s². So, the deceleration is 180.5 m/s².

Now, using the first equation of motion, we have:

$v=u+at\\\\t=\frac{v-u}{a}$

Plug in the given values and solve for 't'. This gives,

$t=\frac{0-9.5}{-180.5}\\\\t=0.053\ s$

Therefore, the the collision will last for 0.053 s.

(a) The collision lasts for 0.053 s.

(b) The deceleration is 180.5 m/s².

8 0

3 years ago

A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift i

bija089 [108]

Answer

Mass m = 78 kg

Vertical height in each stage h = 11 m

(a).

Initial speed u = 0

Final speed v = 1.1 m / s

$v^2=u^2 + 2 as$

$1.1^2 = 2 a \times 11$

a = 0.055 m/s²

Work done

$W_a= m g h + \dfrac{1}{2}mv^2$

$W_a= 78\times 9.8 \times 11 + \dfrac{1}{2} 78 \times 1.1^2$

$W_a = 8408.4 + 47.19$

$W_a = 8455.59 J$

(b).Work done

$W_b= mgh$

W_b = 78× 9.8× 11

$W_b= 8408.4 J$

Work done

$W= m g h + \dfrac{1}{2}m(v_f-v_i)^2$

Where V = final speed

= 0

v = 1.1 m / s

for deceleration a = -0.055 m/s²

now,

$F_L = 56 (-0.055+9.8) = 545.72 N$

W_c = 545.75 × 11

$W_c = 6003.25 J$

7 0

3 years ago

State the law of conservation of momentum<br>

trapecia [35]

Answer:

Law of conservation of momentum states that. For two or more bodies in an isolated system acting upon each other, their total momentum remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed.

Explanation:

Hope it helps

8 0

3 years ago

Read 2 more answers

A black hole in the universe is a An empty region in space b- A massive collapsed star c- A moon that is always turned to its da

marusya05 [52]

Answer:

b. a massive collapsed star

Explanation:

A black hole in the universe is nothing but a massive collapsed star. When the size of the star crosses a particular limit it cannot holds its mass and it collapses under it own self. This is called supernova. A black hole is actually a region in space where gravity is so strong that even light cannot escape through it. Gravity so strong because the matter has been pressed into a tiny space. hence option b is correct

4 0

3 years ago

Why would a landslide be more likely on a steep mountain than on a gently sloping hill?

Serjik [45]

Steep mountain, due to gravity.

4 0

3 years ago

Read 2 more answers