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Mama L [17]
3 years ago
9

Turn this scentence to repirted speach.i ate icecreamShe said that..........​

Physics
2 answers:
kenny6666 [7]3 years ago
7 0
Fvhjgxvbbdfhj if Dan kf xdhgxzsf
Luda [366]3 years ago
5 0

Answer:

dhfhffuththt9tr8tujtngigjtjrjrjrurur

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Electrons move from negative to positive while the voltage flows ________ to _______ .
Sedaia [141]

Answer:

positive to negative.

3 0
2 years ago
How much kinetic energy does a 1500 kg car have if it’s moving at 15 m/s
Tresset [83]

Answer:

Mass of car m = 1500 kg

velocity v = 15 m/s

kinetic energy = ½ mv2

= ½ x 1500 x (15)2    

= 1687501   kg m2 /s2

  = 168750J

Explanation:

6 0
3 years ago
A rocket's mass decreases as it burns fuel. the equation of motion for a rocket in vertical flight can be obtained from newton's
Talja [164]

<span>The equation of motion for a rocket in vertical flight can be obtained from newton’s second law of motion and is constant-mass system. The equation of motion for a body mass varies with time and mass. When force acts on rocket, the rocket will accelerate in the direction of force. Therefore, force is equal to the change in momentum per change in time. For constant mass, force equals mass times acceleration.</span>

4 0
3 years ago
Density of water is 1000 kg/m^3. What will be the volume of 35000 kg water?
d1i1m1o1n [39]
Volume = mass/density
Volume = 35000/1000
Volume = 35m^3
8 0
2 years ago
Suppose that you can throw a projectile at a large enough v0 so that it can hit a target a distance R downrange. Given that you
NikAS [45]

Answer:

Theta1 = 12° and theta2 = 168°

The solution procedure can be found in the attachment below.

Explanation:

The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).

In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.

7 0
3 years ago
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