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3 years ago

Please answer quick!

Mathematics

1 answer:

Assoli18 [71]3 years ago

6 0

Answer:

Step-by-step explanation:

i think it is A because he should have solved it like this:

-2/3 * 5 1/6

-2/3 * 31/6 (convert mixed number into improper fraction)

-1/3 * 31/3 (cross reduction)

-31/9 (multiply fractions)

-3 4/9 (final reduction)

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A process is controlled with a fraction nonconforming control chart with three-sigma limits, n = 100, UCL = 0.161, center line =

photoshop1234 [79]

Answer:

Lets Recall, p= 0.080, n=100, UCL= 0.161

Then np=100, 0.080=8

Step-by-step explanation:

The full steps or solution to this is in an an attached document.

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3 years ago

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3 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

<u><em>Final answer</em></u>:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

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4 years ago

Express 0.77230.77230, point, 7723 as a fraction

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Answer:

7723/10000

Step-by-step explanation:

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3 years ago

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3 years ago