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Viktor [21]
3 years ago
5

The Invisible Hand promotes

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
6 0
The answer to this is D
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The points (-1.6, 2.7) and (3.2, 7.98) are on the graph of a linear relationship between two variables, r and y.
Aleksandr [31]

Answer:

  y = 1.1x +4.46

  y = 129.86 for x = 114

Step-by-step explanation:

The two-point form of the the equation for a line is useful for this.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (7.98 -2.7)/(3.2 -(-1.6))(x -(-1.6)) + 2.7

  y = 5.28/4.8(x +1.6) + 2.7

  y = 1.1x +1.76 +2.7

  y = 1.1x +4.46

__

When x=114, the value of y is ...

  y = 1.1(114) +4.46

  y = 129.86

6 0
3 years ago
Jennifer has a taco stand.she found that her daily costs can be modeled by C(x)=x^2-40x+610. if she wants to keep her daily cost
polet [3.4K]
Let's focus on the given equation. The C represents the cost, while the x must be the number of tacos, which is what we're solving for. Since we're given the boundary that C must be 300, then the solution would be:

300 = x² - 40x + 610
x² - 40x + 310 = 0

Apply the quadratic formula where a = 1, b = -40 and c = 310. The roots of x are:
x = 29.49≈30
x = 10.51≈11

<em>Thus, she needs to sell either 30 or 11 tacos.</em>

4 0
3 years ago
Plz plz help me i really need help
olya-2409 [2.1K]
Area = πr². So you have the diameter which is 56 millimeters. And the radius (r) is half the diameter, so the radius would be 28 mm. Square 28 would be 784, multiplied by π would equal 2463.00864mm. Rounded to the nearest hundredth would be 2843.01mm².

3 0
3 years ago
Graph y = | x | + 5
Elanso [62]

Answer:

(0,5) (0,-5)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write the area A of a square as a function of its perimeter P. ...?
Svetradugi [14.3K]
The answer is A = P²/16

The perimeter P of a square is sum of its sides s: P = s + s + s + s = 4s
The area A of a square with side s is: A = s * s  = s²

Step 1: Solve s from the formula for the perimeter.
Step 2: substitute s from the formula for the perimeter into the formula for the area.

Step 1:
P = 4s
s = P/4

Step 2:
A = s²
s = P/4
A = (P/4)²
A = P²/4²
A = P²/16
4 0
3 years ago
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