Question

Please help me with this problem. Urgent

Answer 1

Answer:

$\frac{x-1}{x^{2} +2x-3}$

$\frac{1}{x+3}$

Step-by-step explanation:

first, subtract the two fractions

You will have

$\frac{x-1}{x^{2} +2x-3}$ the un-simplified difference of those expressions

Lets try to simplify that

Lets find the roots of the polynomial from the bottom using the formula for quadratic equation, (-b +/- sqrt( b2-4*a*c)) /(2*a)

Which are x=-3, and x=1

Thus, you have (x+3)*(x-1)

So

$\frac{x-1}{x^{2} +2x-3} = \frac{x-1}{(x+3) (x-1)}= \frac{1}{x+3}$