Answer:
put it in desmos
Step-by-step explanation:
Answer: 8y4+25y3+60y2+10y+7
Step-by-step explanation:
(y2+3y+7)(8y2+y+1)
=(y2+3y+7)(8y2+y+1)
=(y2)(8y2)+(y2)(y)+(y2)(1)+(3y)(8y2)+(3y)(y)+(3y)(1)+(7)(8y2)+(7)(y)+(7)(1)
=8y4+y3+y2+24y3+3y2+3y+56y2+7y+7
=8y4+25y3+60y2+10y+7
hope this helps!:)
Answer: The approximate area of the circle is: <span>3,629.84 cm² .</span>
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Area of a circle, "A" : A = π * r² ;
in which: A = Area of circle ;
π <span>≈ 3.14 ;
</span> r = radius;
radius of a circle, "r" = d / 2 ; in which: "d = diameter" ;
Given "d = 64 cm " ;
r = d / 2 = 64 cm / 2 = 32 cm ;
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So; A = π * r² ;
A ≈ (3.14) * (32 cm)² ;
A ≈ (3.14) * (1156 cm²) ;
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A ≈ 3,629 .84 cm² .
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Explanation:
f(x) = (x-4)(x+2)
1) For x-intercept, y will be 0
<u />
<u>x-intercept</u>: (4, 0), (-2, 0)
2) For vertex: x = -b/2a where ax² + bx + c
<u>Quadratic function</u>:
<u>vertex</u>:
y: (x-4)(x+2) = (1-4)(1+2) = -9
ordered pair of vertex: (1, -9)
3) For y-intercept, x will be 0
<u>y-intercept</u>: (0, -8)
Answer:
Final answer is 
and 
.
Step-by-step explanation:
Given equation is 
Now we need to find the solution of in given interval ![[0, 2\pi ]](https://tex.z-dn.net/?f=%5B0%2C%202%5Cpi%20%5D)
.
which gives and in the given interval.
Hence final answer is and .
