When the inequality is "...or equal to", the circle must be closed because it will <em>include</em> that value. Based on this, we can eliminate the first and third choices.
Now, you must solve the inequality like any other equation.
![-2r+3\geq 19](https://tex.z-dn.net/?f=-2r%2B3%5Cgeq%2019)
<em>*Subtract 3 from both sides*</em>
![-2r\geq 16](https://tex.z-dn.net/?f=-2r%5Cgeq%2016)
<em>*Divide both sides by -2* </em>(BE CAREFUL: When dividing by a negative in an inequality, you must flip the sign)
![r\leq -8](https://tex.z-dn.net/?f=r%5Cleq%20-8)
The arrow must go to the left since it is "less than..."
The fourth choice is the correct answer.
Hope this helps!!