All categories

2 years ago

1 to 8 plz plz plz help me

Mathematics

1 answer:

e-lub [12.9K]2 years ago

4 0

Answer:

1-8 = -7

Step-by-step explanation:

1 - 8

1 0 -1 -2 -3 -4 -5 -6 -7

You might be interested in

Find the hypotenuse of each isosceles right triangle when the legs are of the given measure. 6 sqrt 2

Gemiola [76]

Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.

There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
$a = b = c \div \sqrt{2} \\ c = a\sqrt{2} \\ c = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12$
Another way to do it is the longer proof of Pythagorean Theorem:
${c}^{2} = {a}^{2} + {b}^{2}... \: \: c = \sqrt{({a}^{2} + {b}^{2})} \\$
$c= \sqrt{({6 \sqrt{2}) }^{2} + ({6 \sqrt{2})}^{2}} \\ = \sqrt{(2 \times{(6 \sqrt{2} )}^{2} )} = \sqrt{2(36 \times 2)} \\ c = \sqrt{144} = 12$

7 0

3 years ago

What is the midpoints of a segment whose endpoints are (-3, 8) and (7, -2) ?

Sidana [21]

$M = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$
$M = (\frac{7 - (-3)}{2}, \frac{-2 + 8}{2})$
$M = (\frac{7 - 3}{2}, \frac{6}{2})$
$M = (\frac{4}{2}, 3)$
$M = (2, 3)$

3 0

3 years ago

How does the distributive property relate to the factoring expression ?

Elena L [17]

Factoring – Using the Distributive Property. A factor is a number that can be divided into another number evenly. For example, the factors of 6 are 1, 2, 3, and 6. ... It means that a number outside the parentheses of an addition problem can be multiplied by each number inside the parentheses.

3 0

2 years ago

What is the area of a sector that has a radius of 25 mm and has an angle measure of 50°?

Nimfa-mama [501]

The area of the sector is 86.81π mm²

<u>Explanation:</u>

Given:

Radius of the sector, 25mm

Angle, α = 50°

Area of the sector, A = ?

We know:

Area of the sector = $\frac{\alpha }{360} X \pi r^2$

On substituting the value, we get:

$A = \frac{50}{360} X \pi X (25)^2\\\\A = 86.81 \pi mm^2$

Therefore, the area of the sector is 86.81π mm²

3 0

3 years ago

Write a polynomial f(x) that satisfies the given conditions. Polynomial of lowest degree with zeros of -2 (multiplicity 3), 3 (m

Genrish500 [490]

Answer:

Step-by-step explanation:

Polynomial f(x) has the following conditions: zeros of -2 (multiplicity 3), 3 (multiplicity 1), and with f(0) = 120.

The first part zeros of -2 means (x+2) and multiplicity 3 means (x+2)^3.

The second part zeros of 3 means (x-3) and multiplicity 1 means (x-3).

The third part f(0) = 120 means substituting x=0 into (x+2)^3*(x-3)*k =120

(0+2)^3*(0-3)*k = 120

-24k = 120

k = -5

Combining all three conditions, f(x)

= -5(x+2)^3*(x-3)

= -5(x^3 + 3*2*x^2 + 3*2*2*x + 2^3)(x-3)

= -5(x^4 + 6x^3 + 12x^2 + 8x - 3x^3 - 18x^2 - 36x - 24)

= -5(x^4 + 3x^3 - 6x^2 - 28x -24)

= -5x^4 - 15x^3 + 30x^2 + 140x + 120

6 0

2 years ago

Read 2 more answers