Answer:
Horizontal distance between lifeguard and the person is 22 feet.
Step-by-step explanation:
Given: A lifeguard sees a person in distress.The eye level of the lifeguard is 15 feet above the ground. Angle of depression is 34°.
To find: Horizontal distance between lifeguard and the person.
Solution : If we draw a triangle then tan∅ = 
Here base is the horizontal distance.
Now we put the values in the formula.
tan 34° = 
Or Base = 
= 
So the answer is 22 feet.
Answer:
cos x (2 sin x − 1)
Step-by-step explanation:
sin(2x) − cos x
Use double angle formula.
2 sin x cos x − cos x
Factor.
cos x (2 sin x − 1)
Answer:
Step-by-step explanation:
the first ine make sense to me
if not right sorry
5 miles high is one of the sides of a triangle depending on accuracy level
h^2=x^2+y^2
we don't have 2 distances
Tan A=O/a
O=a tan A
We solve for O because the angle is at the top of the line going up and we want the opposite angle that is along the ground
O=5×tan(173.7/2)=90.854033512
The distance he can see is:
90.85*2~181.7 miles
Now we need to find the distance between lines:
The north south distance between each line is 69 miles
thus the number of degrees he will see will be:
181.7/69
=2 19/30
Answer:
14.
let me know if you want the steps
