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What is the simplified form of the expression 3 + 8x − 2y − x + 1 + 4y?

jok3333 [9.3K]

Answer:

7x + 2y + 4

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify

3 + 8x - 2y - x + 1 + 4y

Step 2: Simplify

Combine like terms (x): 7x + 3 - 2y + 1 + 4y
Combine like terms (y): 7x + 2y + 3 + 1
Combine like terms: 7x + 2y + 4

8 0

2 years ago

5 yrs ago, Nuri was thrice as old as Sonu. 10 yrs later, Nuri will be twice as old Sonu. How old are Nuri n Sonu?

Papessa [141]

Answer:

Answer will be 50

Step-by-step explanation:

Let us suppose, present age of Nuri be ‘x’ years and present age of Sonu be ‘y’ years.

Now, it is given that five years ago, Nuri was thrice old as Sonu. Hence,

Five years ago,

Nuri’s age = x-5 years

Sonu’s age = y-5 years

And relation between ages can be given as

Nuri’s age = 3×sonu’s age or

x-5 = 3(y-5)

x-5 = 3y-15

x-3y+10 = 0 ………..(i)

Another relation is given in the problem that ten years later, Nuri is twice as old as Sonu.

So, ten years ago,

Nuri’s Age = x+10

Sonu’s Age = y+10

And relation between ages can be written as

x+10 = 2(y+10)

x+10 = 2y+20

x-2y-10 = 0 …………..(ii)

Now we can solve the equation (i) and (ii) to get values of x and ‘y’ or present ages of Nuri and Sonu.

Value of ‘x’ from equation (i) be

x = 3y-10 ……….(iii)

Putting value of ‘x’ from equation (iii) in equation (ii) we get,

3y-10-2y-10 = 0

y = 20

Now, from equation (iii) value of ’x’ can be given as,

x= 3(20)-10

x = 50

Hence, the present ages of Nuri and Sonu are 50 years and 20 years respectively.

7 0

2 years ago

The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta

earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of k success in n samples drawn from a population of size N which include K success. Every draw is either a success of failure.

The random variable X = number of meals that will exceed the cost covered by the company.

The random variable X follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

$P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}$

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

$P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637$

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0

3 years ago

Which equivalent equation is the result of combining like terms in the given equation? 2r + 55 = 6r + 7 – 2r

nikklg [1K]

I hope I help you out

6 0

3 years ago

M- Determine whether or not the procedure described below results in a binomial distribution. If it is not binomial, identify a

Igoryamba

Answer:

A. Yes, the result is a binomial probability distribution.

Step-by-step explanation:

The experiment above depicts a binomial probability distribution because the 4 required conditions are met :

1.) The distribution is independent as the possible outcome of each trial is the same.

2.) There are two possible categories and the result of each trial is one of two outcomes : Yes or No

3.) The number of observation is fixed at sample size of 5500

4.) The probability of success and failure of each trial is the same for all trials in the sample.

Hence, we can conclude that the experiment depicts a binomial probability distribution.

7 0

2 years ago