<h2><em>Answer:</em></h2><h2><em>=</em><em>12</em></h2><h2><em>12step</em><em> </em><em>by step explanation:</em></h2><h2><em>=</em><em>solution:</em></h2><h2><em>solution: area of gym= 144</em></h2><h2><em>solution: area of gym= 144we know that,</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L²</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144)</em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L </em></h2><h2><em>solution: area of gym= 144we know that, area of square= L² or,144= L² or, (12)² = L²(12² means 12×12=144) or, 12= L therefore, L = 12 </em></h2>
Answer:
A. 15
Step-by-step explanation:
V of a right prism which this is. Is LxWxH
So 1.5x 4x2.5=15
Answer:
$-4.90.
Step-by-step explanation:
Fathi has $1.10. Each sheet costs him $0.25. He wants to print 47 pages.
If he prints double sided, then he will use 47 / 2 = 23.5 sheets of paper. But he can't print a half-sheet, so he will use 24 sheets of paper.
Each sheet costs $0.25. 0.25 * 24 = 6. The printing will cost him $6.
Since he only has $1.10, his remaining balance will be 1.1 - 6 = -4.9. The balance on his printing account will be $-4.90.
Hope this helps!
Answer:
<a = 90° (180-90 supplementary angle)
<b = 90° (180-90 supplementary angle)
<d = 48° (180-132 supplementary angle)
<e = 132° (opposite angle)
<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)
Step-by-step explanation:
<a = 90° (180-90 supplementary angle)
<b = 90° (180-90 supplementary angle)
<d = 48° (180-132 supplementary angle)
<e = 132° (opposite angle)
<c = 42° (interior angles of a triangle equal 180. 180-48-90=42)
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
