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natka813 [3]
4 years ago
8

There are ten cards, each has a different number on it, from 1 to 10. Sam took one card, and it was 5 on it. If he takes one of

the remaining cards without looking, what is the probability that the sum of the numbers on his two cards will be smaller than 8?
Mathematics
2 answers:
Akimi4 [234]4 years ago
6 0

there are 9 cards left

1,2,3,4,6,7,8,9,10

the only cards that will make the sum less than 8 is 1 and 2

2/9

Answer: 2/9

Tom [10]4 years ago
6 0

Answer:

<em>2/9</em>

Step-by-step explanation:

The original group of cards consisted of: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

He took a 5.

The current group of cards consists of: 1, 2, 3, 4, 6, 7, 8, 9, 10

Which cards can he take and have a sum less than 8?

5 + 1 = 6   good

5 + 2 = 7    good

5 + 3 = 8    not good

Only the cards with 1 or 2 are good.

There are 9 cards remaining, and he gets the desired outcome from only 2 of those cards.

p(sum less than 8) = 2/9

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Pls help. No files pls. Will give brainliest.
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To find f(-20), first figure out which piece x = -20 fits with.

Since -20 < -12, x = -20 first in the domain used by the third piece.

For f(-20), treat this function as if it was just f(x) = 3x-7.

f(-20) = 3(-20) -7

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3 years ago
Write the fraction 29/7 as a repeating decimal
marshall27 [118]

Answer:

See below.

Step-by-step explanation:

7 ) 29.0

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3 years ago
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Ivanshal [37]
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3 years ago
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asambeis [7]

Answer:

c) 2

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Step-by-step explanation:

We are given the following in the question:

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P(X

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4 0
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Answer:

B

Step-by-step explanation:

29 + (-37) = 29 -37

Leave a like and mark brainliest if this helped

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