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3 years ago

How to solve the problem

Mathematics

1 answer:

scoundrel [369]3 years ago

8 0

$f(x)=x^2+1\\\\f(4)\to\text{put x = 4 to the equation of the function f}\\\\f(4)=4^2+1=16+1=17\\\\\ [f(4)]^2=17^2=289\\\\Answer:\ \boxed{289}$

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Y 45° 30° N 17 I need help pls

melisa1 [442]

Answer:

x=29.4

Step-by-step explanation:

To help find the sides of a triangle, I use SOHCAHTOA.

SOH - CAH - TOA

S=O/H ( $Sine=\frac{opposite}{hypotenuse}$ )

C=A/H ( $Cosine=\frac{adjacent}{hypotenuse}$ )

T=O/A ( $Tangent =\frac{opposite}{adjacent}$ )

Let's find x first. We know 2 parts of the triangle: the adjacent leg, and the angle that is opposite of that.

So it would be tangent (tan).

opposite = 17

adjacent = 30°

Plug these numbers into the calculator and you should get your answer.

$\frac{17}{tan(30)} = 29.44486372...$

x=29.4

Try to do y on your own and let me know if you have any questions!

Also correct me if I'm wrong on anything.

Hope this information helps!

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3 years ago

What is the slope of the line that passes through the points (4, 4)(4,4) and (10, 7) ?(10,7)? Write your answer in simplest form

Mashutka [201]

The slope of line passing through the points (4, 4) and (10, 7) is $\frac{1}{2}$

Solution:

Given that, we have to find the slope of line that passes through the points (4, 4) and (10, 7)

The slope of line passing through $(x_1 , y_1)$ and $(x_2, y_2)$ is given as:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Given two points are (4, 4) and (10, 7)

$\text{ Here } x_1 = 4 ; y_1 = 4; x_2 = 10; y_2 = 7$

Substituting the values in formula, we get

$\begin{aligned}&m=\frac{7-4}{10-4}\\\\&m=\frac{3}{6}\end{aligned}$

Reducing to lowest terms, we get

$m=\frac{1}{2}$

Thus slope of line passing through given points is $\frac{1}{2}$

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san4es73 [151]

Answer:

The correct answer should be B.

I hope this helps!

-Mikayla

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mestny [16]

The ratio would be 3:4, or however you write ratios.

Hope this helped! :)

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3 years ago

Read 2 more answers

Tom [10]

I’m sorry I’m just now I’m sorry I didn’t answer my

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3 years ago