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2 years ago

Is 3x+4y a polynomial. is it is a polynomial, state the degree of the polynomial.

Mathematics

2 answers:

Marina86 [1]2 years ago

6 0

Answer: 3x+4y is a binomial. The binomial is to the first degree. I believe.

Svetlanka [38]2 years ago

5 0

Yes, this is a polynomial. It is an expression containing variables raised to a real number.

In this case, the variables are being raised to the power of one.

The degree of this polynomial, thus, is one.

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Please help with this question<br> 2(2w-6)=6(w-6)+14<br> w=?

IRISSAK [1]

4w-12=6w-36+14
4w-12=6w-22
10=2w

5=w
(I think)

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2 years ago

Use the distributive property to simplify the expression: -4(4x + 3) + (7x - 2)

Elodia [21]

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The answer is -9x -10

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2 years ago

Give an example of how people have used igneous rock. PLSS GIVE ME EXAMPLE PLSSSs

bogdanovich [222]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago

A rectangular flower garden measures 9 ft. by Il ft. About how long is a diagonal path through the garden?

dolphi86 [110]

Answer:

14.212 feet

Step-by-step explanation:

Pythagorean Theorem.

sqrt(9^2+11^2) = 14.212

5 0

2 years ago