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vazorg [7]
2 years ago
9

Convert 37.45 to a fraction

Mathematics
2 answers:
Art [367]2 years ago
5 0

Answer:

37   9/20

Step-by-step explanation:

Leno4ka [110]2 years ago
5 0

Answer:

{ \bf{answer \: is \: { \underline{37 \frac{9}{20} }}}}

Step-by-step explanation:

When converting to fraction, you must get to know about the place values.

3 » tens

7 » ones

.4 » tenth

5 » hundredth

since last place value is hundredth, fraction denominator must be 100

therefore:

37.45 =  \frac{3745}{100}

then you can reduce by 5:

=  \frac{3745 \div 5}{100 \div 5}  \\  \\  =  \frac{749}{20}

In mixed fraction:

= 37 \frac{9}{20}

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Johnny went to an apple farm to pick some apples. The admission to get in was $5.00 and the apples cost $0.75 per pound.
sasho [114]

Answer:

y=0.75x+5

Step-by-step explanation:

It would be this equation because you start at 5, which is the y-intercept, then you add 0.75 for every pound of apples. So on a graph you would start at 5 on the y-line then go up by 0.75

6 0
3 years ago
A car and a bus set out at 2 p.M. From the same point, headed in the same direction. The speed of the car is 30mph slower than t
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Answer:

Car = 10 miles/hour

Bus = 20 miles/hour

Step-by-step explanation:

Here,

Let, the value of the speed of the bus = X

the value of the speed of the car = 2X - 30 (As the speed of the car is 30mph slower than twice)

According to the question,

2X - 20 = 2*(2x-30)

or, 2X - 20 = 4X-60

or, 2X = 40

x = 20

Therefore, the speed of the bus, x = 20 miles/hour

So, the speed of the car is (2*20-30) mph = (40 - 30) mph = 10 miles/hour.

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3 years ago
Externally applied mechanical forces acting on a body, such as normal and shear forces, will cause deformation dependent on the
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Find the answer in the attachment

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A survey of 398 children given at a local elementary school showed that 200 like chocolate ice cream 125 like pistachio ice crea
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3 0
3 years ago
Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the
Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees wasx+\frac{1}{4} x=\frac{5}{4} x, and for the next three years we have that

                             Start                                          End

Second year     \frac{5}{4}x --------------   \frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x

Third year    (\frac{5}{4} )^{2}x-------------(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x

Fourth year (\frac{5}{4})^{3}x--------------(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.

So  the formula to calculate the number of trees in the fourth year  is  

(\frac{5}{4} )^{4} x, we know that all of the trees thrived and there were 6250 at the end of 4 year period, then  

6250=(\frac{5}{4} )^{4}x⇒x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.

Therefore the number of trees at the begging of the 4-year period was 2560.  

7 0
3 years ago
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