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olga2289 [7]
3 years ago
5

Ahmad wants to practice free-throws. He estimates the distance from the free-throw Line to the hoop and marks it with chalk. Ahm

ad’s estimate was 13.5 feet. The actual Distance should be 15 feet. Find the percent of error.
Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer:

10%

Step-by-step explanation:

const2013 [10]3 years ago
4 0

Answer: 10%

Step-by-step explanation:

The difference between his estimated and actual distance is 15 - 13.5 = 1.5

The percentage of error is the difference divided by the actual value.

1.5÷15 = 0.10

Converted to a percentage, it is 10%

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Answer:

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Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given the mean of the Population( )= $290,000

Standard deviation of the Population = $145,000

Given the size of the sample 'n' = 100

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Let   X⁻ = 325,000

Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }  = \frac{325000-290000}{\frac{145000}{\sqrt{100} } }  = 2.413

<u><em>Step(ii):</em></u>-

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413)

                           = 0.5 - A(2.413)

                           = 0.5 - 0.4920

                           = 0.008

<u><em>Final answer:-</em></u>

The probability that the mean of the sample is greater than $325,000

P( X > 3,25,000) = P( Z >2.413) = 0.008

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