How many judges should be selected to estimate the population mean wage with 90% confidence and a margin of error of $2.00
1 answer:
Answer:
The number of judges that should be selected is 25
Step-by-step explanation:
Given that:
The C.I = 90%
Level of significance = 1 - C.I
= 1 - 0.90
= 0.10
Critical level for
at 0.10 = 1.645
The margin of error E = 2.00
Let's assume that the sample standard deviation was $6.11
Then;
The number of judges that should be selected can be computed by using the formula:
![E = Z_{\alpha/2} \times \dfrac{s}{\sqrt{n}}](https://tex.z-dn.net/?f=E%20%3D%20Z_%7B%5Calpha%2F2%7D%20%5Ctimes%20%20%5Cdfrac%7Bs%7D%7B%5Csqrt%7Bn%7D%7D)
![2 = 1.645 \times \dfrac{6.11}{\sqrt{n}}](https://tex.z-dn.net/?f=2%20%3D%201.645%20%5Ctimes%20%20%5Cdfrac%7B6.11%7D%7B%5Csqrt%7Bn%7D%7D)
![2\sqrt{n} = 10.05095](https://tex.z-dn.net/?f=2%5Csqrt%7Bn%7D%20%3D%2010.05095)
![\sqrt{n} = \dfrac{10.05095}{2}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D%20%5Cdfrac%7B10.05095%7D%7B2%7D)
![\sqrt{n} =5.026](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D%20%3D5.026)
![n=(5.026)^2](https://tex.z-dn.net/?f=n%3D%285.026%29%5E2)
n = 25.26
n ≅ 25
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