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tamaranim1 [39]
3 years ago
13

A bus makes a stop at 2:30, letting off 15 people and letting on 9. The bus makes another stop ten minutes later to let off 4 mo

re people. How many more or fewer people are on the bus after the second stop compared to the number of people on the bus before the 2:30 stop?
Mathematics
2 answers:
laila [671]3 years ago
6 0

Answer: The answer is 19 fewer people.


Step-by-step explanation:  Given that the bus makes first stop at 2:30 where it let off 15 people and let on 9 people.

So, the total number of peoples in the bus before 2:30 = 15+9 = 24.

Again, after 10 minutes, the bus makes another stop letting off 4 more people there. So, the number of people remained in the bus after second stop

= 9-4 = 5.

Therefore, the difference in the number of peoples before 2:30 and after the second stop = 24-5 = 19.

Thus, there remains 19 fewer people than the number of peoples in the bus before 2:30.


nika2105 [10]3 years ago
4 0
(-19)+9=-10, so there is 10 less people on the bus

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Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

To begin with, let's establish that ( x ) can equal to any number from 0 to 9.

Meaning, that ( x ) is equal to one of the following: 0, 1, 2, 3, 4, 5, 6, 7, 8 or 9.

Now that we know which values ( x ) can equal to, we will simply substitute each of the numbers as potential values of ( x ) into the six-digit number and divide it by 27 to see if it is a multiple of 27.

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