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3 years ago

HELP PLEASEEE HELPPPPPPPPPPPPPP

Mathematics

1 answer:

Anna71 [15]3 years ago

6 0

Answer: B

Explanation:

slope is rise over run which is also $\frac{y}{x}$ .

$\frac{y}{x}$ = $\frac{AmountEarned}{TimeWorked(h)}$

which can be stated as: amount earned per hour (h)

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If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$

Now,

$a^2 - b^2 = (a-b) (a+b)$

and

$a - b = \sqrt3 - \sqrt{11} + \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{9\sqrt3 - 7\sqrt{11}}8$

$a + b = \sqrt3 - \sqrt{11} - \dfrac{\sqrt3 + \sqrt{11}}8 = \dfrac{7\sqrt3 - 9\sqrt{11}}8$

$\implies a^2 - b^2 = \dfrac{\left(9\sqrt3 - 7\sqrt{11}\right) \left(7\sqrt3 - 9\sqrt{11}\right)}{64} = \boxed{\dfrac{441 - 65\sqrt{33}}{32}}$

5 0

2 years ago

What do I need to make on my next quiz if I have an f and quizzes are 30% of our grade?

hram777 [196]

Make more than a 80 on quizzes and you should be fine 75 lowest possible

3 0

3 years ago

Have you ever sent a chain letter or chain e-mail or text? Best Friend Test Sample email chain letter: This is a best friend tes

Anna007 [38]

Answer:

what? Is this like a challenge or something?

6 0

4 years ago

Here's a question ~

Gre4nikov [31]

Answer:

(0, 5√3/2 + 2)

Step-by-step explanation:

Given is the absolute value function.

Observations:

It has a slope of ±√3 and the y- intercept of 2.
There is no horizontal shift, so the the y-axis is the line of symmetry.
The y-axis is also an angle bisector of the two lines.
The foot P₁P₂ is parallel to the x-axis since it's perpendicular to the y- axis.

We need to find the coordinates of intersection of the line P₁P₂ with the y- axis (the point Y in the picture).

Consider the triangle AYP₂.

We know AP₂ = 5.

The angle YAP₂ is:

arctan (1/√3) = 30°

The distance AY is:

AY = AP₂ cos 30° = 5*√3/2

The distance from the x-axis to the point Y is:

5√3/2 + 2, added the y- intercept of the graphed lines

The coordinates of the point Y:

(0, 5√3/2 + 2)

3 0

3 years ago

U.S. postal regulations require that a package can have a maximum combined length and girth (distance around) of 108 in. A shipp

Eduardwww [97]

Answer: The maximum length that can be used is 56 inches.

Step-by-step explanation:

Since we have given that

Width of package = 14 inch

Height of package = 12 inch

Let the length of package be 'l'.

Combined length and girth i.e. distance around = 108 inches.

So, According to question, we get that

$l+2(w+h)=108\\\\l+2(14+12)=108\\\\l+2\times 26=108\\\\l+52=108\\\\l=108-52\\\\l=56\ inches$

Hence, the maximum length that can be used is 56 inches.

4 0

4 years ago