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2 years ago

The vertex of this parabola is at (2,-4). When the y value is -3, the x-value is

1 answer:

4 0

$\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \textit{we know that } \begin{cases} h=2\\ k=-4 \end{cases}\implies y=a(x-2)^2-4 \\\\\\ \textit{we also know that } \begin{cases} y = -3\\ x = -3 \end{cases}\implies -3=a(-3-2)^2-4\implies 1=a(-5)^2 \\\\\\ 1=25a\implies \boxed{\cfrac{1}{25}=a}$

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Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
x = $\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}$ Plug in your values
x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
x = 1 $\pm \frac{ \sqrt{6} }{2}$ Simplify $\frac{ \sqrt{6} }{2}$ to $\sqrt{ \frac{3}{2} }$
x = 1 $\pm \sqrt{ \frac{3}{2} }$

4 0

3 years ago

4x^2+5y^2=41 3x^2-4y^2=23

dybincka [34]

Answer:

i dont know the answer sry

Step-by-step explanation:

srryyy

5 0

2 years ago

A customer works into a post office to purchase stamps. she purchases a total of 45 stamps. some of the stamps are 49cent stamps

baherus [9]

Step-by-step explanation:Let number of 49 cents =A

Let number of 33 cents=B

A+B=45 equation 1

1 $=100 cents

49 cents =.49 dollar

33 cents=.33 dollar

so .49A+.33B=17.89 equation 2

Add equation 1 and equation 2

since these are simultaneous equations

.49A+.33B=17.89

A+ B=45

so divide equation 2 by 100 we get

49A+33B=1789

A+B =45 multiply equation 1 by 33 on both the sides we get

33A+33B=1485 equation 3

so subtract equation 3 from equation 2 we get

49A+33B=1789 equation 2

33A+33B=1485 equation 3

16A+0 =304

16A=304

A=304/16

A=19

putting nalue of A in equation 1 we get

A+B=45

19+B=45

B=45-19

B=26

so number of 49 cent stamps are 19

and number of 33 cent stamps are 26

5 0

2 years ago

Which Statement is true ?

elena55 [62]

F(-4)=G(-4) because when the two lines cross over the f line is at the -4 and same with G

7 0

2 years ago

The image of the point (3, -4) under a translation is (0, –5). Find the coordinatesof the image of the point (8,7) under the sam

Sav [38]

We will have the following:

*First: We determine the translation rule:

We have that the point went from (3, -4) to (0, -5), thus the translation rule would be:

$(x,y)\to(x-3,x-1)$

Second: We apply the translation rule to the other point to determine it's image, that is:

$(8,7)\to(8-3,7-1)\to(5,6)$

So, the image of the second point is (5, 6).

6 0

11 months ago