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sashaice [31]
3 years ago
13

Rearrange x=3g+2 to make g the subject

Mathematics
2 answers:
Vinil7 [7]3 years ago
5 0
The answer for ur question is
x=3g+2
x-2=3g
(x-2)/3 =g
g= (x-2)/3

HOPE THIS HELPS !!!

^_^ HAPPY TO HELP YA ^_^



Elina [12.6K]3 years ago
3 0
(x-2)÷3=g here it is
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What would be the value of the number in the 30th position
REY [17]
If I saw that correctly each position that's your multiplier so look at your 3rd position and make the 3 into a 30 so it would be 270 :)
4 0
4 years ago
Can someone help me ​
Naily [24]

Answer:

mhm what is that

Step-by-step explanation:

4 0
3 years ago
Solve.<br> y=-x-2<br> y=4x+3
adelina 88 [10]
1) Equal the two together (not including the ‘y’)

-x -2 = 4x + 3

2) put x together and the whole number together
* when switching sides, signs ( + & -) changes, watch out for that *

-x - 4x = 3 + 2
-5x = 5 divide by the # with x so you have x
—— ——-
-5. -5
x = -1

therefore, x = -1


For y just plug x into either equation
I’ll use y = 4x + 3

y = 4(-1) + 3
y = -4 + 3
y = -1

therefore, y = -1

5 0
3 years ago
Someone please help me I’m so confused!!!
QveST [7]

Answer:

number one.  186in^{2}  number two.  36cm^{2}

Step-by-step explanation:

FOR NUMBER ONE:

the area of a trapezoid formula is   \frac{a+b}{2} h where a and b are the bases and h is the height. so we have to add in the numbers into the formula

\frac{12+15}{2} * 6\\ = <em>81</em>

and the paralellogram formula is b×h.  where b is the base and h is height

15 × 7 = <em>105</em>

so the area of the figure is 81 + 105 is 186 in^2

FOR NUMBER TWO:

the area of the square formula is s^{2}.   where s is the side

4^2 = <em>16</em>

and for the paralellogram is b × h

4 × 5 = <em>20</em>

so the area of the figure is 16 +20 = 36 in^2

hope this helps! ;)

5 0
3 years ago
The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui
mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

s(t) = -16t^2+v_0t+s_0

Where,

s_0 = initial height of the object,

v_0 = initial velocity of the object,

Here,

s_0=400\text{ feet}

v_0=35\text{ feet per sec}

Hence, the height of the ball after t seconds,

s(t)=-16t^2+35t+400

When s(t) = 0,

\implies -16t^2+35t+400=0

t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}

t=\frac{-35\pm \sqrt{1225+25600}}{-32}

\implies t\approx -4.02\text{ or }t\approx 6.21

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0
3 years ago
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