(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
Bottom left corner and bottom right corner
Step-by-step explanation:
The anwser to your question is 1 and 5/7
Answer:
n=100+0.05(460)
Step-by-step explanation:
She earns 100 dollars all the time. so its 100+ something
she also earns 5% of the tips, which in that case were 460$
you can repersent that as 0.05(460)
so: 100+0.05(460)
It has to be the first one
