The difference between the sum of all eight positive integral divisors of 66 and the sum of all eight positive integral divisors of 70 is zero.
<h3>How to find the difference between the integral divisors?</h3>
First let's find the integral divisors. We can write 66 as a product of prime numbers as:
66 = 33*2 = 2*3*11
Then the integral divisors of 66 are:
2
3
11
2*3 = 6
2*11 = 22
3*11 = 33
1 (trivially)
66 (trivially)
The sum gives:
2 + 3 + 11 + 6 + 22 +33 + 1 + 66 = 144
For 70 we have:
70 = 7*10 = 2*5*7
Then the integral divisors are:
1
70
2
5
7
2*5 = 10
2*7 = 14
5*7 = 35
The sum gives:
1 + 70 + 2 +5 + 7 + 10 + 14 + 35 = 144
Then the difference between these two sums is:
144 - 144 = 0
If you want to learn more about integral divisors:
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Answer:
X = 8, Y = 8
Step-by-step explanation:
Step 1) Solve for Y w/ bottom equation to yield - y = -2/3x + 40/3.
Step 2) substitute equation into x + y = 16 to get 1/3x + 40/3 = 16 multiply by 3 to clear the fractions and get x + 40 = 48 - subtract 40 by both sides to get x = 8.
Step 3) Plug x = 8 into the bottom equation to get 48 + 9y = 120, subtract 48 by both sides to get 9y = 72 and then divide by 9. The product is y = 8.
Answer:
use photomath and your welcome :)))
Answer:
Explanation:
f ( −
3
) basically means substitute −
3 for x in the function −
5
x
f
(
−
3
)
=
−
5
(
−
3
)
−
7
f
(
−
3
)
=
15
−
7
f
(
−
3
)
=8
Step-by-step explanation:
Answer:
b.
Step-by-step explanation:
hope it's help
<h2>to all</h2>
