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lorasvet [3.4K]
3 years ago
15

I need help with 21 and 22. please.

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0

21. A

22. G                                

I Am writing this part because it said that the answer didnt have enough characters so just ignore this

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Amy runs a bike rental business. She currently charges $36 per bike
Aneli [31]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
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If x = 3k + 2 and y = k - 2 is a solution of linear equation 5x - 3y = 4 , then the value of k
Andrej [43]

Answer:

It is given that 5x−3y=k

Now by substituting the value of x and y in the equation

5(3)−3(4)=k

So we get

15−12=k

k=3

Therefore, the value of k is 3

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4 0
3 years ago
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E is the midpoint of Df, DE=2x+4, and EF=3x-1. Find all segment lengths
sertanlavr [38]
If E is the midpoint, DE and EF are equivalent.
2x+4=3x-1
4=x-1
5=x

Plug the value of x in
2(5)+4
14

3(5)-1
14

14+14=28

Final answer: DE=14, EF=14, DF= 28
6 0
4 years ago
What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

5 0
3 years ago
A light bulb filament is one-hundredth of an inch thick, with an allowable error of 2 percent. What is the least allowable thick
Andreyy89

Answer:

0.00998 Inches

Step-by-step explanation:

Thickness of the light bulb filament = 0.01 Inch

Allowable error = 2%.

2% of 0.01 = 0.02 X 0.01 =0.0002 Inch

Therefore, the allowable thickness of the bulb filament

=0.01 \pm 0.0002 $ Inches

We can then calculate the least allowable thickness of the filament as:

=0.01 - 0.0002 \\=0.00998$ Inches

The least allowable thickness of the filament is 0.00998 Inches.

3 0
4 years ago
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