Answer:
b
Step-by-step explanation:
Answer:
It is given that 5x−3y=k
Now by substituting the value of x and y in the equation
5(3)−3(4)=k
So we get
15−12=k
k=3
Therefore, the value of k is 3
Askmeanything2♡
If E is the midpoint, DE and EF are equivalent.
2x+4=3x-1
4=x-1
5=x
Plug the value of x in
2(5)+4
14
3(5)-1
14
14+14=28
Final answer: DE=14, EF=14, DF= 28
Given:
The function is:

To find:
The initial value of the function.
Solution:
We have,

The value of the function at x=0 is called the initial value of the function.
For x=0, we get


Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.


Therefore, the initial value of the function is 350.
Answer:
0.00998 Inches
Step-by-step explanation:
Thickness of the light bulb filament = 0.01 Inch
Allowable error = 2%.
2% of 0.01 = 0.02 X 0.01 =0.0002 Inch
Therefore, the allowable thickness of the bulb filament

We can then calculate the least allowable thickness of the filament as:

The least allowable thickness of the filament is 0.00998 Inches.