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Leya [2.2K]
3 years ago
9

89 more than the quotient of an unknown number and 62 is 94

Mathematics
1 answer:
Nataly [62]3 years ago
6 0
X/62 + 89 = 94

x/62 +89 = 94 
  <u>      - 89   - 89</u>
x/62         = 5
*<u> 62            *62</u>
            x = 310

To check:
quotient of an unknown number and 62
310/62 = 5

5 + 89 = 94
94 = 94

5 is the quotient of an unknown number and 62.
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Find the 10th term of the geometric sequence whose common ratio is 2/3 and whose first term is 3.
Sergeu [11.5K]

Answer:

\frac{512}{6561}

Step-by-step explanation:

1) if according to the condition a₁=3 and r=2/3, then a₁₀ can be calculated as:

a₁₀=a₁*r⁹;

2) according  to the rule above:

a₁₀=3*(2/3)⁹=512*3/(6561*3)=512/6561.

5 0
2 years ago
Can someone help out I’m confused.
iragen [17]

Answer:

y=-2/5x-3

Step-by-step explanation:

the slope is m and the y intercept is b

8 0
2 years ago
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Day, everything at a store is on sale. The store offers a 20% discount.
Nutka1998 [239]

Answer:

$14.40

Step-by-step explanation:

$18-20%=$14.40

4 0
2 years ago
I need help very important
siniylev [52]

Answer:

∠ EFG = 83°, ∠ GCE = 97°

Step-by-step explanation:

Since FE and FG are tangents to the circle then

∠ FGC and ∠ FEC are right angles

The sum of the angles in quadrilateral CEFG = 360°

Sum the 4 angles and equate to 360

3x + 11 + 90 + 5x - 23 + 90 = 360, that is

8x + 168 = 360 ( subtract 168 from both sides )

8x = 192 ( divide both sides by 8 )

x = 24

Thus

∠ EFG = 3x + 11 = 3(24) + 11 = 72 + 11 = 83°

∠ GCE = 5x - 23 = 5(24) - 23 = 120 - 23 = 97°

4 0
3 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
100.8 \: kg - 20.35 \: kg = 80.45 \: kg

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
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