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SCORPION-xisa [38]

3 years ago

11

Which expression is a irrational number? A. 0.78 repeating

2 answers:

katen-ka-za [31]3 years ago

6 0

Answer:

The answer is C. Square root √18

Step-by-step explanation:

you are looking for irrational number.

if use a calculator and you see that the √18 is 4.242642687119285 is a non-terminated number and non-repeated number so its irrational

the other three is rational because you can turn them into a fraction and we don't want that.

Oxana [17]3 years ago

4 0

<span>An irrational number has an infinite decimal expansion that does not repeat. Numbers that have infinite decimal expansions that do not repeat </span>cannot<span> be expressed as the fraction of two integers.

</span>A rational number is any number that can be expressed as the fraction of two integers.

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$15.~f(g(2))=\Large\boxed{11}\\$

$16.~g(f(2.5))=\Large\boxed{16}$

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Step-by-step explanation:

<h3>Given information</h3>

$f(x)=x+4$

$g(x)=2x+3$

<h3>Question 15. f(g(2))</h3>

<u>Substitute values into the first function</u>

$g(2)=2(2)+3$

$g(2)=4+3$

$g(2)=7$

<u>Substitute the values of the first function into the second</u>

$f(g(2))=f(7)$

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<h3>Question 16. g(f(2.5))</h3>

<u>Substitute values into the first function</u>

$f(2.5)=(2.5)+4$

$f(2.5)=6.5$

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<u>Substitute the values of the first function into the second</u>

$g(f(2.5))=g(6.5)$

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<h3>Question 17. g(f(-5))</h3>

<u>Substitute values into the first function</u>

$f(-5)=(-5)+4$

$f(-5)=-1$

<u>Substitute the values of the first function into the second</u>

$g(f(-5))=g(-1)$

$g(-1)=2(-1)+3$

$g(-1)=-2+3$

$g(-1)=\Large\boxed{1}$

<h3>Question 18. f(g(-5))</h3>

<u>Substitute values into the first function</u>

$g(-5)=2(-5)+3$

$g(-5)=-10+3$

$g(-5)=-7$

<u>Substitute the values of the first function into the second</u>

$f(g(-5))=f(-7)$

$f(-7)=(-7)+4$

$f(-7)=\Large\boxed{-3}$

Hope this helps!! :)

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