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9966 [12]
3 years ago
15

Subtract. 99.28 8.87​

Mathematics
2 answers:
Kipish [7]3 years ago
6 0
99.28 - 8.87 = 90.41
Yuliya22 [10]3 years ago
5 0
99.28 - 8.87 = 90.41
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Find the unique permutations of the letters of the word : CEASELESS
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Answer:

There are 2,520 unique permutations.

Step-by-step explanation:

When we have a set of N different elements, the total number of permutations is given by:

P = N! = N*(N - 1)*(N - 2)*...*(2)*(1)

Particularly, if out of these N elements, there are a given element that is repeated K times, then the permutations of these K elements actually do not add new unique permutations, then in that case the total number of unique permutations is:

P = N!/K!

And if we have another element that is repeated L times, then with the same reasoning than above, the total number of unique permutations is:

P = N!/(K!*L!)

Now, we have the set:

{C, E, A, S, E, L, E, S, S}

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K = 3

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P = \frac{9!}{3!*3!}  = \frac{9*8*7*6*5*4*3*2*1}{3*2*1*3*2*1} = \frac{9*8*7*6*5*4}{3*2*1} = 2,520

So there are 2,520 unique permutations.

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Step-by-step explanation:

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