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sergejj [24]
3 years ago
12

What is the side length of s on the square A=m²​

Mathematics
1 answer:
quester [9]3 years ago
4 0
The side length of s on the same square would be P = 4a
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Jonathan replaced the original factory tires (P220/65 R 18) on his pickup truck with (P255/60 R 17) tires. Calculate the circumf
svet-max [94.6K]

Answer:

92 inches

Step-by-step explanation:

When a tire's size = P220/65 R 18, it means that:

  • the rim is 18 inches wide (or 457 millimeters)
  • the width of the tire is 8.7 inches (or 220 millimeters)
  • the sidewall of the tire is 5.65 inches (or 144 millimeters)
  • the 65 shows the relationship between tire width and sidewall (65%)

the total diameter of the tire = 5.65 + 18 + 5.65 = 29.3 inches

the circumference = 2 x π x radius   or   diameter x π = 29.3 x 3.141592 = 92 inches

3 0
3 years ago
Read 2 more answers
Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance
zzz [600]

Answer:

\frac{\Delta v}{v}=0.426

Step-by-step explanation:

you have that the average sped is given by the following formula:

v(x,t)=\frac{x}{t}

The uncertainty formula for a division is given by:

\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}        (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0
3 years ago
The average weight of the entire batch of the boxes of cereal filled today was 20.5 ounces. A random sample of four boxes was se
zhenek [66]

Answer:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

Step-by-step explanation:

For this case we have the following dataset given:

20.05, 20.56, 20.72, and 20.43

We can assume that the distribution for the sample mean is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for this case would be:

SE= \frac{\sigma}{\sqrt{n}}

And we can estimate the deviation with the sample deviation:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s= 0.286

And then the estimator for the standard error is given by:

SE= \frac{0.286}{\sqrt{4}}= 0.143

4 0
3 years ago
PLEASE HELP I WILL MARK BRANLIEST
liubo4ka [24]
31.62
You use pythagorean theorem so 30 is legA and 10 is legB so 20^2+10^2= square root legC which is 31.62
8 0
3 years ago
Hello,can you answer this question asap thxs
Ivan

9514 1404 393

Answer:

  111 1/9 pounds

Step-by-step explanation:

The given relationship is ...

  delivered = ground × (1 -10%)

Then ...

  ground = delivered/0.90 = 100 lb/0.90 = 111 1/9 lb

It is necessary to grind 111 1/9 pounds of grain to have exactly 100 lb after a 10% payment.

5 0
2 years ago
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