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Yuri [45]
3 years ago
9

Look at image please help me asap

Mathematics
2 answers:
AysviL [449]3 years ago
7 0
Answer is b^2 (extra characters)
Lynna [10]3 years ago
3 0

Answer:  b^2

You can write this as b^2

===================================================

Work Shown:

c = \frac{(ab^5)^{1/2}}{(ab)^{1/2}}\\\\c = \left(\frac{ab^5}{ab}\right)^{1/2}\\\\c = \left(b^4\right)^{1/2}\\\\c = b^{4*1/2}\\\\c = b^{2}\\\\

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Are the set of all square numbers under 50 and the set of all triangular numbers that are less than 50 disjoint?
Alina [70]

Answer:

No, the two sets are not disjoint.

Step-by-step explanation:

Set of triangular numbers to 50: 1, 3, 6, 10, 15, 21, 28, 36, 45

Set of square numbers to 50: 1, 4, 9, 16, 25, 36, 49

They have 1 and 36 in common, so they are not disjoint, or in other words, they have some of the same numbers.

7 0
3 years ago
(5x10^3)x(9x10^7) can someone please answer this for me.
Anna11 [10]
4.5 times 10^10

1. Multiply 5times ten to the third

2. Multiply 9 times ten raised to the seventh

Then multiply them together
5000 times 90000000
5 0
3 years ago
Which of the following is the same as 1.207 x 107?
melisa1 [442]

Answer:

C. Or the third option

Step-by-step explanation:

When you multiply something by a power of ten the decimal moves either left or right by the exponent. That probably sounds really confusing but here are some examples. If you multiply a number by 10^4 the decimal will move right 4 places making the number larger. Meanwhile if you multiplied it by 10^-4  it will move to the left 4 places making the number smaller. In your case, when you multiply 1.207 by 10^7, the decimal moves  places to the right which makes it 12,070,000

8 0
3 years ago
Two slits are illuminated by a 348 nm light. The angle between the zeroth-order bright band at the center of the screen and the
Andre45 [30]

Answer:0.369 m

Step-by-step explanation:

Given

Distance between slit and screen is D=154 cm

Wavelength \lambda =348 nm

Angle between zeroth order bright fringe and Fourth-order bright fringe is \theta =13.5^{\circ}

let distance between the slits be d

Distance of n th bright fringe From central Fringe is given by

y_n=\frac{nD\lambda }{d}

Also \tan \theta =\frac{y_4}{D}

y_4=\tan (13.5)\cdot 1.54

y_4=0.24\times 1.54

y_4=0.369 m

5 0
3 years ago
Solve for the following if x = 6: (Hint: substitute 6 for the letter x and work the problem. You will work more with substitutio
MrRa [10]
If x=6 it is
9. 5
10. 18
11. 23
12. 5.5
13.68
if x=3 it is
2
15
8
11
41
5 0
2 years ago
Read 2 more answers
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