Answer:
1/24
Step-by-step explanation:
![\sf \left[\begin{array}{cc}\sf 4&\sf 6\\ \sf 5 &\sf 8 \\ \sf 3 &\sf -2\end{array}\right]-\left[\begin{array}{cc}\sf 2&\sf 3\\ \sf 1 &\sf 4 \\ \sf -5&\sf3\end{array}\right]](https://tex.z-dn.net/?f=%5Csf%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%204%26%5Csf%206%5C%5C%20%5Csf%205%20%26%5Csf%208%20%5C%5C%20%5Csf%203%20%26%5Csf%20-2%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%202%26%5Csf%203%5C%5C%20%5Csf%201%20%26%5Csf%204%20%5C%5C%20%5Csf%20-5%26%5Csf3%5Cend%7Barray%7D%5Cright%5D)
Just substract corresponding terms
![\\ \sf\longmapsto \left[\begin{array}{cc}\sf 2 &\sf 3\\ \sf 4&\sf4\\ \sf 8&\sf -5\end{array}\right]](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Csf%202%20%26%5Csf%203%5C%5C%20%5Csf%204%26%5Csf4%5C%5C%20%5Csf%208%26%5Csf%20-5%5Cend%7Barray%7D%5Cright%5D)
Option B
Answer:
y =47.5.
Step-by-step explanation:
First eliminate the fractions by multiplying through by the LCM of 7 and 3 which is 21:
21* 6[y-2]/7-21*12 = 21*2[y-7]/3
18(y - 2) - 252 = 14(y - 7)
18y -36 - 252 = 14y - 98
18y - 14y = -98 + 36 + 252
4y = 190
y = 190/4
y = 47.5.
Suppose the height of the prism is 1 in, then the volume will be:
volume=length×width×height
thus
volume of the prism will be:
V=3×1/2×1
V=1.5 in³
Volume of the cube will be:
v=1×1×1=1 in³
Thus the number of cubes that will be in the prism will be:
(1.5 in³)/(1 in³)
=1.5 cubes~2 cubes
Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector 
is a linear combination of 
and 
if there are two scalars 
such as
In our case, all the vectors are given in 
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of 
and 
, so the solution is
