The correct answer is In2O3 < Ga2O3 < Al2O3.
Ga2O3, Al2O3, and In2O3 are the oxides to rank in order of increasing aqueous acidity.
According to the contemporary periodic table's rule, an oxide group's acidity decreases.
The oxidation state of Gallium (Ga) in Ga2O3 = +3
The oxidation state of Aluminium (Al) in Al2O3 = +3
The oxidation state of Indium (In) in In2O3 = +3
From modern periodic table, the order of elements in group 3A is as below:
Baron (B), Aluminum (Al), Gallium (Ga), Indium (In), and Thallium (Tl)
Thus, we can get the oxides in order of increasing their aqueous acidity as below:
In2O3 < Ga2O3 < Al2O3
To learn more about aqueous acidity refer the link:
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Missing question:
Suppose Gabor, a scuba diver, is at a depth of 15 m. Assume that:
1. The air pressure in his air tract is the same as the net water pressure at this depth. This prevents water from coming in through his nose.
2. The temperature of the air is constant (body temperature).
3. The air acts as an ideal gas.
4. Salt water has an average density of around 1.03 g/cm^3, which translates to an increase in pressure of 1.00 atm for every 10.0 m of depth below the surface. Therefore, for example, at 10.0 m, the net pressure is 2.00 atm.
T = 37°C = 310 K.
p₁ = 2,5 atm = 253,313 kPa.
p₂ = 1 atm = 101,325 kPa.
Ideal gas law: p·V = n·R·T.
n₁ = 253,313 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₁ = 0,589 mol.
n₂ = 101,325 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₂ = 0,2356 mol.
Δn = 0,589 mol - 0,2356 mol = 0,3534 mol.
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That it is negatively charged
