Answer:
The concentration of the newly prepared solution is 8 * 10^-5 M
Explanation:
The most common way to solve this problem is to use the following formula
c1*V1 = c2*V2
with c1 = 1 * 10^-3 M
with V1 = 20 mL = 0.02 L
with c2 = TO BE DETERMINED
with V2 = 250 mL = O.250 L
10^-3 * 0.02 L = c2 * 0.250L
0.00002 = c2 * 0.250L
c2 = 0.00002 / 0.250 L
c2 = 0.00008 M = 8 * 10^-5 M
The concentration of the newly prepared solution is 8 * 10^-5 M
First step: The mass of zinc in the yellow zinc sample can be calculated with the help of percentage (given) in the sample. After that, mass of copper is determine by the subtracting the mass of zinc from the total mass of zinc in the given sample.
Thus,
Mass of zinc in 34% zinc sample = 
=
zinc
Mass of zinc in 37% zinc sample = 
=
zinc
Now,
mass of copper in 34% zinc sample =
= 
mass of copper in 37% zinc sample = 
=
Thus, the range of mass of copper is
to 
Second step:
34% zinc sample consist of 66% copper (100-34= 66%)
37% zinc sample consist of 63% copper (100-37=63%)
Mass of zinc = 
= 
Mass of zinc =
= 
Thus, the range of mass of zinc is
to 
Answer:
It's 120 g
Explanation:
I'm doing that question on ck12 and it's correct.
Answer:
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