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Lilit [14]
3 years ago
15

3.79 rounded to the nearest tenth

Mathematics
1 answer:
creativ13 [48]3 years ago
7 0
3.79

Look at the hundredth place, see if it's 5 or higher or 4 or lower.
Since it is 5 or higher, we round the tenth place up.

3.8
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Solve the system of equations y = x + 5 and y = 5x - 11 using a graphical method.
tresset_1 [31]

You can use substitution for this.

x+5 = 5x -11

Combine like terms

16=4x

Divide 4 on both sides to isolate the x

x=4

Plug x=4 to one of the equations

y= 4 +5

Combine like terms

y=9

So the answer is A. (4,9)

I hope this helps you out a bunch hun :)

4 0
3 years ago
Anita can clean a typical pool in 8 hours. Chao can clean a typical pool in 6 hours. How long should it take Anita and Chao work
Snezhnost [94]
This kind of problems requires to add the working velocities. The total velocity is the sum of the individual velocities.

Anita's velocity = 1 pool/8 hours
Chao's velocity = 1 pool/6 hours

Combined velocity 1/8 + 1/6 = (3 + 4)/24 = 7/24 pool/hour

Time = 1 pool / (7/24) pool/hour = 24/7 hour =3.43 hours
8 0
3 years ago
Kiran has 10 1/2 feet of lumber and wants to make a bookshelfKiran needs two side panels that are each 5 2/3 feet. How much more
eimsori [14]

Total height of lumber, H = 10 1/2 feet = 21/2 feet .

Height of side panel, h = 5 2/3 feet = 17/3 feet .

Now,

Extra lumber required, L = 2 × Height of side panel - Total height of lumber

L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet

Therefore, extra lumber required is \dfrac{5}{6} feet.

Hence, this is the required solution.

4 0
3 years ago
You and a partner tend 3 machines that run continuously. One prints 200 plastic bottles per hour, one prints 180 plastic bottles
strojnjashka [21]
The first machine does 200 in 1 hour, so in 8.5 hours it will then do 200 * 8.5.

the second machine does 180 in 1 hour, so in 8.5 hours it will then do 180 * 8.5.

the third machine does 150 in 1 hour, so in 8.5 hours it will do then 150 * 8.5.

how many bottles will they all do in total on that time?

(200 * 8.5) + (180 * 8.5) + (150 * 8.5)
6 0
3 years ago
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Suppose sin(A) = 1/4. use the trig identity sin^2(A)+cos^2(A)=1 to find cos(A) in quadrant II. around to ten-thousandth.
larisa86 [58]

In quadrant II, \cos(A) will be negative. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = -\sqrt{1 - \sin^2(A)} = -\dfrac{\sqrt{15}}4 \approx \boxed{-0.9682}

8 0
2 years ago
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