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Nataly_w [17]
3 years ago
13

Find the value of b that makes

la1" title=" x^{2} +bx+\frac{9}{4} " alt=" x^{2} +bx+\frac{9}{4} " align="absmiddle" class="latex-formula"> a perfect square trinomial
Mathematics
1 answer:
ahrayia [7]3 years ago
3 0
Perfect square trinomial is like

(x+4)^2=x^2+8x+16
they are represented as such
ax^2+bx+c
so to solve for b you do
(√c) times 2=b so

c=9/4
square root=3/2 because 3/2 times 3/2=9/4
(√(9/4)) times 2=(3/2) times 2=6/2=3
so b=3

x^2+3x+(9/4)
if factored, it gives
(x+(3/2))(x+(3/2))  or
(x-(3/2))(x-(3/2))


if this equation is equal to 0 then x=-3/2 or 3/2

the value is 3
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7 0
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Read 2 more answers
HELP PLEASE 21 POINTS PLEASE HELP ME!!!! &lt;3
Anna007 [38]

1)

n         1          2         3           4         5         6

f(n)    1033    932     831      730     629     528

First term (a₁):  <u>1033 </u>          Common difference (d): <u>-101 </u>

Explicit rule:  a_{n} = 1134 - 101n    Recursive rule: a_{n} = a_{n-1} - 101

a_{n} = a_{1} + d(n - 1)

a_{n} = 1033 - 101(n - 1)

a_{n} = 1033 - 101n + 101

a_{n} = 1134 - 101n

***********************************************************************************

2)

n         1          2         3           4         5         6

f(n)   -39      -29       -19        -9          9        19

First term (a₁):  <u> -39  </u>          Common difference (d): <u> +10  </u>

Explicit rule:  a_{n} = -49 + 10n    Recursive rule: a_{n} = a_{n-1} + 10

a_{n} = a_{1} + d(n - 1)

a_{n} = -39 + 10(n - 1)

a_{n} = -39 + 10n - 10

a_{n} = -49 + 10n

***********************************************************************************

3)

n         1          2         3           4         5         6

f(n)   3.75      2.5     1.25        0      -1.25     -2.5

First term (a₁):  <u> 3.75  </u>          Common difference (d): <u> -1.25  </u>

Explicit rule:  a_{n} = 5 - 1.25n    Recursive rule: a_{n} = a_{n-1} - 1.25

a_{n} = a_{1} + d(n - 1)

a_{n} = 3.75 - 1.25(n - 1)

a_{n} = 3.75 - 1.25n + 1.25

a_{n} = 5 - 1.25n


6 0
3 years ago
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