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Makovka662 [10]
3 years ago
15

9 -3(x - 2) + 3x = 9​

Mathematics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

u cant solve it

Step-by-step explanation:

because if u distribute the -3 to x you get -3x, then add 3x and u have 0x to the problem is false cause u cancelled out x

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A pile of string measures to be 4 5/6 feet long. For a project Ms. Thompson wants to cut the long piece of string into several s
Vesnalui [34]

Answer:

7 pieces

Step-by-step explanation:

change 4 5/6 into an irregular fraction. 29/6

divide 29/6 by 2/3. to do this, flip and multiply

29/6 * 3/2 = 87/12 = 7.25 or 7 whole pieces

3 0
3 years ago
Olga Decorat blankets with ribbon she has 12 yards of ribbon she uses 22 feet of the ribbon to decorate blankets after she decor
andre [41]

Answer:

  14 feet

Step-by-step explanation:

There are 3 feet in 1 yard, so 36 feet in 12 yards. The remaining ribbon will be the original amount less the amount used.

  36 - 22 = 14 . . . . feet remaining

3 0
3 years ago
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ddd [48]

Answer:

The answer is

\frac{26}{31}

GOOD LESSONS ♡

7 0
2 years ago
Mackenzie has $70 in a savings account. The interest rate is 5%, compounded annually.
sladkih [1.3K]

Answer:

She will have $73.5 in 1 year

Step-by-step explanation:

She has $70 and the interest rate is 5% so we need to add 5% to the initial value

x = $70 + $70 * 5%

5% = 5/100

x = $70 + $70 * 5/100

x = $70 + $3.5

x = $73.5

She will have $73.5 in 1 year

8 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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