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3 years ago

9 -3(x - 2) + 3x = 9

Mathematics

1 answer:

olga55 [171]3 years ago

6 0

Answer:

u cant solve it

Step-by-step explanation:

because if u distribute the -3 to x you get -3x, then add 3x and u have 0x to the problem is false cause u cancelled out x

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8.4.9 On or off the line & Practice Problems

Andrews [41]

Answer:

Number of quarters → 15

Number of dimes → 2

Step-by-step explanation:

Let the number of dimes I have = y

And number of quarters = x

Since, I have amount in my pocket = $2

Therefore, 0.10y + 0.25x = 2

100(0.10y + 0.25x) = 100×2

25x + 10y = 200

5x + 2y = 40

2y = -5x + 40

y = -2.5x + 20 ---------(1)

Total number of coins in my pocket = 17

x + y = 17

y = -x + 17 ---------(2)

By using a graphing calculator we can graph these two lines (As attached)

Solution of the given system of equations will be the point of intersection of these lines.

Solution → (2, 15)

Number of quarters → 15

Number of dimes → 2

4 0

3 years ago

Find the discriminant of 3x^2-10x=-2

Oksanka [162]

Answer:

Step-by-step explanation:

given a quadratic equation in standard form : ax² + bx + c = 0 : a ≠ 0

then the discriminant is Δ = b² - 4ac

given 3x² - 10x = - 2 ( add 2 to both sides )

3x² - 10x + 2 = 0 ← in standard form

with a = 3, b = - 10 and c = 2

b² - 4ac = (- 10)² - (4 × 3 × 2) = 100 - 24 = 76

7 0

3 years ago

Pls help me due soon

KIM [24]

Answer:

I'm pretty sure it b

Step-by-step explanation:

I think its b

5 0

3 years ago

A line passes through the points (–3, –4) and (6, 2). What number is the x-intercept?

LuckyWell [14K]

Answer:

Step-by-step explanation:

$\bold{METHOD\ 1}$

$\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\\text{x-intercept:}\ (x,\ 0).\\\\\text{Susbtitute the coordinates of the points to the formula of a slope}\\\\(-3,\ -4),\ (6,\ 2),\ (x,\ 0):\\\\m=\dfrac{2-(-4)}{6-(-3)}=\dfrac{2+4}{6+3}=\dfrac{6}{9}=\dfrac{6:3}{9:3}=\dfrac{2}{3}\\\\m=\dfrac{0-2}{x-6}=\dfrac{-2}{x-6}\\\\\text{Therefore we have the equation:}\\\\\dfrac{-2}{x-6}=\dfrac{2}{3}\qquad\text{cross multiply}\\\\2(x-6)=(-2)(3)\\\\2(x-6)=-6\qquad\text{divide both sides by 2}\\\\x-6=-3\qquad\text{add 6 to both sides}\\\\x=3$