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klasskru [66]
3 years ago
10

Algebra 2, please help! thank you

Mathematics
2 answers:
Hunter-Best [27]3 years ago
7 0

Answer:

-2pi/3

Step-by-step explanation:

y = 2 cos 3(x + 2π∕3) +1

y = A sin(B(x + C)) + D  

amplitude is A

period is 2π/B

phase shift is C (positive is to the left)

vertical shift is D

We have a shift to the left of 2 pi /3

Alika [10]3 years ago
3 0

Answer:

A

Step-by-step explanation:

The standard cosine function has the form:

\displaystyle y = a\cos (b(x-c)) + d

Where |<em>a</em>| is the amplitude, 2π / <em>b</em> is the period, <em>c</em> is the phase shift, and <em>d</em> is the vertical shift.

We have the function:

\displaystyle y = 2 \cos 3\left(x + \frac{2\pi}{3}\right) + 1

We can rewrite this as:

\displaystyle y = \left(2\right)\cos 3\left(x - \left(-\frac{2\pi}{3}\right)\right) + 1

Therefore, <em>a</em> = 2, <em>b</em> = 3, <em>c</em> = -2π/3, and <em>d</em> = 1.

Our phase shift is represented by <em>c. </em>Thus, the phase shift is -2π/3.

Our answer is A.

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