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labwork [276]
3 years ago
14

Some bank robbers leave town, speeding at 71 mph. Twelve minutes later, the police give chase, traveling at 80 mph. How long, af

ter the robbery will it take the police to overtake the robbers.
Mathematics
1 answer:
Inga [223]3 years ago
5 0

The police is traveling at a speed of 80 kmh while the bank robbers are traveling at a speed of 70kmh so the Police is 10kmh more than the robbers that means the police is more faster and will take 10kmh to catch up the bank robbers
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An aerodynamic three-wheeled automobile (the Dart) runs on compressed natural gas stored in two cylinders in the rear of the veh
pogonyaev

Answer:

a) 7702.88 miles

b) If we drive more than 7702.88 miles per year, the dart would be more economical.

Step-by-step explanation:

Assuming a useful life of 7 years.

Let's calculate EUAC dart:

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= 15000 * 0.2054 + 0.08

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EUAC For other automobile:

(12000)(A/P, 10%, 7) + (X/50mpg)(8)

= 12000 * 0.2054 + 0.16X

= 2464.92 + 0.16X

a) To solve for X, we have:

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3081.15 + 0.08X = 2464.92 + 0.16X

0.08X - 0.16X = 2464.92 - 3081.15

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X = 7702.88 miles

b) The range of annual miles driven is the Dart more economical.

EUAC dart < EUAC other automobile

3081.15 + 0.08X < 2464.92 + 0.16X

X > 7702.88 miles

If we drive more than 7702.88 miles per year, the dart would be more economical.

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3 years ago
In ΔABC, m∠ACB = 90°, CD ⊥ AB and m∠ACD = 45°. Find AC, if CD = 6 sqrt 3
Alla [95]

Answer:

6\sqrt{6}\ un.

Step-by-step explanation:

Consider right triangle ABC with right angle ACB. If m∠ACD = 45°, then

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Since  CD ⊥ AB, then

m∠CDA=m∠CDB=90°.

Thus, triangles ACD and BCD are right triangles with right angles ADC and BDC. In these triangles:

m∠CAD=90°-m∠ACD=90°-45°=45°;

m∠CBD=90°-m∠BCD=90°-45°=45°.

Thus, triangles ACD and BCD are isosceles right triangles with

CD=AD=BD=6\sqrt{3}\ un.

By the Pythagorean theorem,

AC^2=CD^2+AD^2,\\ \\AC^2=(6\sqrt{3})^2+(6\sqrt{3})^2,\\ \\AC^2=216,\\ \\AC=6\sqrt{6}\ un.

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Answer:

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