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dezoksy [38]
3 years ago
9

Melissa’s birthday is in a week and she has been receiving cardsin the mail with different amounts of money. She has received 5

cards with the following amounts: $10, $20, $25, $30, $40. If Melissa receives one more card in the mail with $25, will the mean increase, decrease, or stay the same?
Mathematics
2 answers:
Evgesh-ka [11]3 years ago
7 0
The mean will stay the same (125 divided by 5 = 25 and 150 divided by 6 = 25)
Damm [24]3 years ago
4 0
Stay the same amount of 25.
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kykrilka [37]
Nonlinear because it is squared it is a quadratic
4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%7D%7Bx%2B1%7D%20%2B%5Cfrac%7B3%28x-1%29%7D%7Bx%7D%20%3D5" id="TexFormula1" title=
Luden [163]

Answer:

x=-3

Step-by-step explanation:

<u>Given equation</u>:

\dfrac{2x}{x+1}+\dfrac{3(x+1)}{x}=5

Make the <u>denominators</u> the same:

\implies \dfrac{2x}{x+1} \cdot\dfrac{x}{x}+\dfrac{3(x+1)}{x} \cdot \dfrac{x+1}{x+1}=5

\implies \dfrac{2x^2}{x(x+1)}+\dfrac{3(x+1)^2}{x(x+1)} =5

<u>Combine</u> the fractions:

\implies \dfrac{2x^2+3(x+1)^2}{x(x+1)} =5

<u>Multiply</u> both sides by x(x+1):

\implies 2x^2+3(x+1)^2 =5x(x+1)

<u>Expand</u> the brackets:

\implies 2x^2+3(x^2+2x+1) =5x^2+5x

\implies 2x^2+3x^2+6x+3 =5x^2+5x

<u>Combine</u> like terms:

\implies 5x^2+6x+3=5x^2+5x

<u>Subtract</u> 5x² from both sides:

\implies 6x+3=5x

<u>Subtract</u> 5x from both sides:

\implies x+3=0

<u>Subtract</u> 3 from both sides:

\implies x=-3

Learn more about algebraic fractions here:

brainly.com/question/27943438

brainly.com/question/27979364

5 0
2 years ago
Mei subscribed to a magazine at a rate of $24 for 12 issues. When she placed her order, Mei used a coupon that added 3 free bonu
Delvig [45]

Answer:

It didn't

Step-by-step explanation:

This is because the coupon adds them for free, this means that one week she got 15 instead of 12. This had no effect on the cost of her perscription because it was free.

8 0
3 years ago
Read 2 more answers
Guys!!! I need help ASAP!!!!
loris [4]
<h2><u>Solution 1</u> :</h2>

Cost of 1\frac{1}{3}pounds of gummy bears = $4.40

Cost of 1 pound of gummy bears :

= 4.40 \div 1 \frac{1}{3}

=  \frac{440}{100}  \div  \frac{4}{3}

=  \frac{440}{100}  \times  \frac{3}{4}

=  \frac{1320}{400}

=  \frac{1320 \div 20}{400 \div 20}

=  \frac{66}{20}

=  \frac{66 \div 2}{20 \div 2}

=  \frac{33}{ 10 }

= 3 \frac{3}{10}

= \color{plum}\bold{\$3.3}

Therefore, 1 pound of gummy bears = <u>$3.3</u>

<h2><u>Solution 2</u> : </h2>

Cost of 1 pound of gummy bears = $3.3

Money Daniel has = $1.00

Quantity of gummy bears he can afford :

= 1 \div 3.3

= 1 \div 3 \frac{3}{10}

= 1 \div  \frac{33}{10}

= 1 \times  \frac{10}{33}

=  \frac{10}{33}

= 0.30

Therefore, Daniel will be able to buy <u>0.30 pounds</u> of gummy bears from Jio.

8 0
3 years ago
Please answer this correctly
Vinil7 [7]

Answer:

V =113.04 cm^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

V = 3.14 (3)^2 4

V = 3.14 *9*4

V =113.04 cm^3

7 0
3 years ago
Read 2 more answers
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