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Rainbow [258]
4 years ago
9

mol/h of benzene in a form of liquid at initial temperature of 300 K is heated to 500 K in a heat exchanger at a constant pressu

re (3 bar). At the final temperature, the benzene has totally changed into vapour form. If the saturated temperature of benzene at 3 bar is 392.3 K, calculate the heat required by the heat exchanger in kW. Assume ideal gases.
Chemistry
1 answer:
koban [17]4 years ago
6 0

Answer:

275?

Explanation:

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What happens when additional electrons were placed in the atom?
EleoNora [17]
They aren't actually placed into the atom, they surround it in the "electron cloud" but if you add electrons, the charge of your atom becomes negative. If your remove them, the charge becomes positive
3 0
4 years ago
A volume of 120 mL of H2O is initially at room temperature (22.00 ∘C ). A chilled steel rod at 2.00 ∘C ∘C is placed in the water
aliina [53]

Answer:

\large \boxed{\text{28.5 g}}

Explanation:

There are two heat flows in this process and, since energy (heat) can neither be destroyed nor created, the energy change for the system must equal zero.

Data:

For Fe,    m₁ = ?;         C₁ = 0.452 J°C⁻¹g⁻¹; Ti =   2.00 °C; T_f = 21.50 °C

For H₂O, m₂ = 120 g; C₂ = 4.18    J°C⁻¹g⁻¹; Ti = 22.00 °C; T_f = 21.50 °C

Calculations:

1. Temperature changes

ΔT₁ = T_f - Ti = 21.50 °C -   2.00 °C = 19.50 °C

ΔT₂ = T_f - Ti = 21.50 °C - 22.00 °C = -0.50 °C

2. Mass of steel rod

\begin{array}{ccl}\text{Heat  gained by steel rod + heat lost by water} & = & 0\\m_{1}C_{1} \Delta T_{1} + m_{2}C_{2} \Delta T_{2}& = & 0\\m_{1} \times 0.452 \text{ J$^{\circ}$C$^{-1}$g$^{-1}$}\times 19.50 \, ^{\circ}\text{C} + \text{120 g} \times 4.18\text{ J$^{\circ}$C$^{-1}$g$^{-1}$} \times (-0.50)\, ^{\circ}\text{C}& = & 0\\8.814m_{1}\text{ g}^{-1} - 250.8 & = &0\\\end{array}\\

\begin{array}{ccl}8.814m_{1}\text{ g}^{-1} & = &250.8\\m_{1} & = & \dfrac{250.8}{\text{8.814 g}^{-1}}\\\\& = & \textbf{28.5 g}\\\end{array}\\\text{The mass of the steel rod is $\large \boxed{\textbf{28.5 g}}$}

6 0
3 years ago
In an aqueous chloride solution cobalt(II) exists in equilibrium with the complex ion CoCl42-. Co2 (aq) is pink and CoCl42-(aq)
kolezko [41]

Answer:

1. This reaction is <u>(A) Exothermic .</u>

2. When the temperature is decreased the equilibrium constant, K: <u>(A) Increases</u>

3.When the temperature is decreased the equilibrium concentration of Co2:<u> (A) Increases</u>

Explanation:

CoCl4^2-(aq)  Co_2+(aq) + 4Cl^-(aq)

1. The pink color predominates at low temperatures, indicating that the commodity is preferred.

This is a reaction that is <u>exothermic.</u>

2. As the decrease in the temperature , the equilibrium constant , K ;

      equilibrium constant = \frac{product}{reactant} =\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}

As the temperature drops, the concentration ofCl^- and CO^2^+ rises, and K rises as well , thus it <u>increases </u>.

3. The equilibrium concentration of CO^2^+ decreases as the temperature decreases:

When the temperature is lowered, the equilibrium shifts to the right , that is it <u>increases.</u>

4 0
3 years ago
Temperature and Thermal Er
gtnhenbr [62]

Explanation:

50 degrees fahrenheit =

10 degrees celsius

7 0
3 years ago
Read 2 more answers
Does anyone know what Yttrium(II) Dichromate's formula would look like?
White raven [17]

Answer:

YCr2O7

Explanation:

3 0
3 years ago
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