They aren't actually placed into the atom, they surround it in the "electron cloud" but if you add electrons, the charge of your atom becomes negative. If your remove them, the charge becomes positive
Answer:

Explanation:
There are two heat flows in this process and, since energy (heat) can neither be destroyed nor created, the energy change for the system must equal zero.
Data:
For Fe, m₁ = ?; C₁ = 0.452 J°C⁻¹g⁻¹; Ti = 2.00 °C; T_f = 21.50 °C
For H₂O, m₂ = 120 g; C₂ = 4.18 J°C⁻¹g⁻¹; Ti = 22.00 °C; T_f = 21.50 °C
Calculations:
1. Temperature changes
ΔT₁ = T_f - Ti = 21.50 °C - 2.00 °C = 19.50 °C
ΔT₂ = T_f - Ti = 21.50 °C - 22.00 °C = -0.50 °C
2. Mass of steel rod


Answer:
1. This reaction is <u>(A) Exothermic .</u>
2. When the temperature is decreased the equilibrium constant, K: <u>(A) Increases</u>
3.When the temperature is decreased the equilibrium concentration of Co2:<u> (A) Increases</u>
Explanation:

1. The pink color predominates at low temperatures, indicating that the commodity is preferred.
This is a reaction that is <u>exothermic.</u>
2. As the decrease in the temperature , the equilibrium constant , K ;
equilibrium constant =
=![\frac{[CO^2^+][Cl^-^4]}{CoCl^2^-_4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCO%5E2%5E%2B%5D%5BCl%5E-%5E4%5D%7D%7BCoCl%5E2%5E-_4%7D)
As the temperature drops, the concentration of
and
rises, and K rises as well , thus it <u>increases </u>.
3. The equilibrium concentration of
decreases as the temperature decreases:
When the temperature is lowered, the equilibrium shifts to the right , that is it <u>increases.</u>