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kow [346]
3 years ago
15

Does anyone know what Yttrium(II) Dichromate's formula would look like?

Chemistry
1 answer:
White raven [17]3 years ago
3 0

Answer:

YCr2O7

Explanation:

You might be interested in
What is the mole ratio needed to determine the mass of phosphorus trifluoride produced from the reaction of 120 g of phosphorus
Vitek1552 [10]

Answer:

\frac{4molPF_3}{1molP_4}

Explanation:

Hello

In this case, given the reaction:

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

It means that since the coefficients preceding phosphorous and phosphorous trifluoride are 1 and 4, the correct mole ratio should be:

\frac{4molPF_3}{1molP_4}

Because given the mass of phosphorous it is convenient to convert it to moles and then cancel it out with the moles on bottom of the mole ratio.

Bes regards!

8 0
3 years ago
At constant pressure increasing the temperature of a fixed amount of gas will do what
Naddika [18.5K]

Answer:

For a fixed mass of gas at constant pressure, the volume is directly proportional to the kelvin temperature. That means, for example, that if you double the kelvin temperature from, say to 300 K to 600 K, at constant pressure, the volume of a fixed mass of the gas will double as well.

5 0
3 years ago
At what temperature a gas with volume 175 L at 15 oC and 760mmHg will occupy a volume of 198 L at a pressure 640mmHg?
MrRissso [65]

Answer:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

T

1

P

1

V

1

=

T

2

P

2

V

2

where,

P_1,V_1\text{ and }T_1P

1

,V

1

and T

1

are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2P

2

,V

2

and T

2

are the final pressure, volume and temperature of the gas

We are given:

\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}

P

1

=760mmHg

V

1

=175L

T

1

=15

o

C=[15+273]K=288K

P

2

=640mmHg

V

2

=198L

T

2

=?K

Putting values in above equation, we get:

\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}

288K

760mmHg×175L

=

T

2

640mmHg×198L

T

2

=274K

Hence, the temperature when the volume and pressure has changed is 274 K

7 0
3 years ago
How many hours is 10:00 am to 4:45 pm?
Maslowich
The answer is 5 hours 45 minutes

4 0
3 years ago
Which of these stores chemical energy?
4vir4ik [10]

Answer:

b

Explanation:

its like that la i know cuz i smart

3 0
3 years ago
Read 2 more answers
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