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trapecia [35]
3 years ago
13

The Titanic was found in 1985 lying on the bottom of the North Atlantic at a depth of 2.5 miles. What is the pressure at this de

pth?
Physics
1 answer:
yan [13]3 years ago
3 0

Answer:

<em>39428.93 N/m²</em>

Explanation:

Pressure: This can be defined as the force acting normally perpendicularly per unit area of surface. The S.I unit of pressure is N/m²

The pressure in a fluid is given as

P = ρgh............................. Equation 1

Where P = pressure, ρ = density, h = height, g = acceleration due to gravity.

Note: The North Atlantic is an ocean, and it contains water

Given: h = 2.5 mile  

If  1 mile =

1 609.344 meters,

Then 2.5 miles = (1609.344×2.5 ) m = 4023.36 m.

Constant: g = 9.8 m/s², ρ = density of water = 1.0 g/m³

Substituting these values into equation 1

P = 1×4023.36×9.8

p = 39428.93 N/m²

<em>Thus the pressure at that depth = 39428.93 N/m²</em>

<em> </em>

<em> </em>

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Her average speed is 0.25 miles / hour.

Explanation:

I did 0.5 divided by 2 = 0.25 miles / hour.

<em>Hope this helps! :)</em>


8 0
3 years ago
Salmon often jump waterfalls to reach their
natta225 [31]

Answer:

5.0 m/s

Explanation:

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v_x = u cos \theta

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d=v_x t = (ucos \theta)t

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Along the vertical direction, the equation of motion is

y=h+u_y t -\frac{1}{2}gt^2

where:

y = 0.311 m is the final height reached by the salmon

h = 0 is the initial height

u_y = u sin \theta is the vertical component of the initial velocity of the salmon

g=9.81 m/s^2 is the acceleration of gravity

t is the time

Substituting t as found in eq.(1), we get the equation

y=(u sin \theta) \frac{d}{u cos \theta}- \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}=d tan \theta - \frac{1}{2}g\frac{d^2}{u^2 cos^2 \theta}

and we can solve this formula for u, the initial speed of the salmon:

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4 years ago
Un móvil se desplaza con una rapidez inicial de 100 km/h, se le aplican los frenos con una
KIM [24]

Answer:

in English please I am quite puzzled

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3 years ago
A 20-turn coil of area 0.32 m2 is placed in a uniform magnetic field of 0.055 T so that the perpendicular to the plane of the co
makvit [3.9K]

Answer:

1.5 * 10^-2 Tm^2

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B = 0.055 T

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theta = 30

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5 0
3 years ago
A beam of light has a wavelength of 4.5 x10^-7 meter in a vacuum. the frequency of this light is
valkas [14]
The basic relationship between frequency and wavelength for light (which is an electromagnetic wave) is
c= f \lambda
where c is the speed of light, f the frequency and \lambda the wavelength of the wave. 
Using \lambda=4.5 \cdot 10^{-7} m and c=3 \cdot 10^8 m/s, we can find the value of the frequency:
f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{4.5 \cdot 10^{-7} m}=6.7 \cdot 10^{14} Hz
3 0
3 years ago
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