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3 years ago

The magnetosphere of Jupiter is

Physics

1 answer:

BartSMP [9]3 years ago

3 0

Answer:

d. a large region outside Jupiter occupied by its magnetic field and filled with high-energy charged particles.

Explanation:

A magnetic field is generated by the movement of a charged particle in the space around it. For the case of Jupiter its magnetic field is created by the liquid metallic hydrogen in its core.

So the magnetosphere is just the magnetic field around a planet, which interacts with high-energy charged particles (for example: Cosmic Rays).

Magnetospheres protect planets from the extreme radiation coming from stars or another interstellar source.

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What class lever is a

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should be 1

Explanation:

because what do you use in class and has a lever

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3 years ago

A driving car around a track is an example of projectile motion

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Answer:

False. It is propelled but projectile is a specific term denoting air friction only after release of energy.

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4 years ago

Green light (λ = 518 nm) strikes a single slit at normal incidence. What width slit will produce a central maximum that is 3.00

MariettaO [177]

Answer:

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

$d\times sin\theta=m\times \lambda$

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

$sin\theta=\frac {\lambda}{d}\times m$ ....1

The location of the bright fringe is determined by :

$y=L\times tan\theta$

Where, L is the distance between the slit and the screen.

For small angle , $sin\theta=tan\theta$

So,

Formula becomes:

$y=L\times sin\theta$

Using 1, we get:

$y=L\times \frac {\lambda}{d}\times m$

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

$0.0150\ m=2.00\ m\times \frac {518\times 10^{-9}\ m}{d}\times 1$

<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>

7 0

3 years ago

A rigid massless rod is rotated about one end in a horizontal circle. There is a particle of mass m1 attached to the center of t

Rzqust [24]

Answer:

m₁/m₂ =8

Explanation:

Writing the centripetal force equation: where T₁ is inner tension and T₂ is outer tension

T₂ = m₂ × ω²R....equation 1

T₁-T₂ = m₁ × ω²R/2

Also T₁=5T₂

5T₂-T₂ = m₁ × ω²R/2

4 × 2T₂ = m₁ × ω²R

8T₂ = m₁ × ω²R

dividing it by equation 1

8 = m₁/m₂

Hence m₁/m₂ =8

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3 years ago

5) Quiz - NO links

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3 years ago