Answer:
a) 12.74 V
b) Two pairs of diode will work only half of the cycle
c) 8.11 V
d) 8.11 mA
Explanation:
The voltage after the transformer is relationated with the transformer relationshinp:
the peak voltage before the bridge rectifier is given by:
The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:
As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.
The averague voltage on a full wave rectifier is given by:
Using Ohm's law:
Answer: +2.10V
Explanation:
Using Nernst equation :
where,
= standard emf for the cell = +2.20 V
n = number of electrons in oxidation-reduction reaction = 6
= emf of the cell = ?
= concentration =
= concentration =
Now put all the given values in the above equation, we get:
The standard emf for the cell using the overall cell reaction below is +2.10 V
Answer:
The angle of the launch is 17.09 degrees.
Explanation:
Given that,
The initial speed of a cannon is 100 m/s
It is launched at some angle and it lands after being in the air for 6 s.
We need to find the angle of the launch.
The time taken by the projectile to reach the ground is called the time of flight. It is given by the formula as follows :
Here, = launch angle
Hence, the angle of the launch is 17.09 degrees.