Answer:
The runner's average acceleration is 0.102 m/s²
Explanation:
The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m
We need to find the runner's average acceleration
The given is:
→ Initial velocity 5 m/s
→ Final velocity 5.2 m/s
→ Distance 10 meters
→ Acceleration ?
We need a suitable rule for the given
→ v² = u² + 2 a s
where v is the final velocity, u is the initial velocity, a is the acceleration
and s is the distance
Substitute the values above in the rule
→ (5.2)² = (5)² + 2 a (10)
→ 27.04 = 25 + 20 a
Subtract 25 from both sides
→2.04 = 20 a
Divide both sides by 20
→ a = 0.102 m/s²
<em>The runner's average acceleration is 0.102 m/s²</em>
Answer:
The answer to your question is: F = 924 N
Explanation:
Data
v = 28 m/s
m = 66 kg
d = 56 cm
F = ?
Formula
v = d/t
a = v/t
F = ma
Process
t = d/v = 56 / 28 = 2 s
a = v/t = 28 / 2 = 14 m/s²
F = 66 (14) = 924 N
Answer:
All the answers are solved and explained below.
Explanation:
Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.
Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).
Data Given:
m = 1000 kg
F = 2000N
t = 10s
Q1 Solution:
Acceleration = a = ?
F = ma
a = F/m
a = 2000/ 1000
a = 2 
Q2: Solution:
Change in velocity = Δv = ?
acceleration = change in velocity / time
a = Δv/t
Δv = axt
Δv = 2 x 10
Δv = 20 m/s
Q3: Solution:
Impulse = I = ?
Impulse = Force x time
I = 2000 x 10
I = 20000 Ns
Q4: Solution:
Change in Momentum = Δp = ?
Δp = mΔv
Δp = 1000 x 20
Δp = 20000 Kgm/s
Q5: Solution:
Final velocity of the car at the end of 10 seconds = vf = ?
Δp = m x Δv
Δp = m x (vf-vi)
Δp = 1000 x (vf - 0 )
20000 = 1000 x vf
vf = 20000/1000
vf = 20 m/s
Q6: Solution:
Change in momentum the car experiences as it continues at this velocity?
Δp = ?
Δp = mΔv
Δp = m x (0)
Δp = 0
Q7: Solution:
Impulse = Change in momentum
Impulse = Δp
Implulse = 0
Q8: Solution:
Change in momentum = Δp = mΔv
Δp = m(vf-vi)
Δp = 1000 x (0-20)
Δp = -20000 kgm/s
Q9: Solution:
Impulse = Δp
Impulse = -20000 Ns
Q10: Solution:
Impulse = ?
Impulse = F x t
F = impulse/t
F = -20000/4s
F = -5000 N
Q11: Solution:
F = ma
a = ?
a = F/m
a = -5000/1000
a = -5
Answer:
4.617 s
Explanation:
The speed of 60 mi/h can be converted to m/s:
(60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s
The relationship between speed and acceleration is ...
v = at
t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s
It will take the car 4.617 seconds to reach 60 mi/h starting from rest.
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