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balandron [24]
3 years ago
13

Distinguish between pressure and force

Physics
1 answer:
Naddika [18.5K]3 years ago
3 0
Force is (mass × acceleration) measured in Newton

Pressure is the 'force' per unit area measured in Newton/m^2 (pascal)
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8. During the last few kilometers of a marathon, runners play mental games to test each
o-na [289]

Answer:

The runner's average acceleration is 0.102 m/s²

Explanation:

The runner accelerates from 5 m/s to 5.2 m/s and covering 10 m

We need to find the runner's average acceleration

The given is:

→ Initial velocity 5 m/s

→ Final velocity 5.2 m/s

→ Distance 10 meters

→ Acceleration ?

We need a suitable rule for the given

→ v² = u² + 2 a s

where v is the final velocity, u is the initial velocity, a is the acceleration

and s is the distance

Substitute the values above in the rule

→ (5.2)² = (5)² + 2 a (10)

→ 27.04 = 25 + 20 a

Subtract 25 from both sides

→2.04 = 20 a

Divide both sides by 20

→ a = 0.102 m/s²

<em>The runner's average acceleration is 0.102 m/s²</em>

3 0
3 years ago
A car traveling at 28.0 m/s28.0 m/s hits a bridge abutment. A passenger in the car, who has a mass of 66.0 kg,66.0 kg, moves for
netineya [11]

Answer:

The answer to your question is: F = 924 N

Explanation:

Data

v = 28 m/s

m = 66 kg

d = 56 cm

F = ?

Formula

v = d/t

a = v/t

F = ma

Process

                          t = d/v = 56 / 28 = 2 s

                          a = v/t = 28 / 2 = 14 m/s²

                          F = 66 (14) = 924 N

6 0
4 years ago
1. What is the value of the acceleration that the car experiences? 2. What is the value of the change in velocity that the car e
tankabanditka [31]

Answer:

All the answers are solved and explained below.

Explanation:

Note: This questions lacks the initial and most necessary data to answer these following questions. I have found a related question. I will be considering that question to carry out the answers.

Question: A car with a mass of 1000 kg is at rest at a spotlight. when the light turns green, it is pushed by a net force of 2000 N for 10 s. (This was the information missing in this question).

Data Given:

m = 1000 kg

F = 2000N

t = 10s

Q1 Solution:

Acceleration = a = ?

F = ma

a = F/m

a = 2000/ 1000

a = 2 m/s^{2}

Q2: Solution:

Change in velocity = Δv = ?

acceleration = change in velocity / time

a = Δv/t

Δv = axt

Δv = 2 x 10

Δv = 20 m/s

Q3: Solution:

Impulse = I = ?

Impulse = Force x time

I = 2000 x 10

I = 20000 Ns

Q4: Solution:

Change in Momentum = Δp = ?

Δp = mΔv

Δp = 1000 x 20

Δp = 20000 Kgm/s

Q5: Solution:

Final velocity of the car at the end of 10 seconds = vf = ?

Δp = m x Δv

Δp = m x (vf-vi)

Δp = 1000 x (vf - 0 )

20000 = 1000 x vf

vf = 20000/1000

vf = 20 m/s

Q6: Solution:

Change in momentum the car experiences as it continues at this velocity?

Δp = ?

Δp = mΔv

Δp = m x (0)

Δp = 0

Q7: Solution:

Impulse = Change in momentum

Impulse = Δp

Implulse = 0

Q8: Solution:

Change in momentum = Δp = mΔv

Δp = m(vf-vi)

Δp = 1000 x (0-20)

Δp = -20000 kgm/s

Q9: Solution:

Impulse = Δp

Impulse = -20000 Ns

Q10: Solution:

Impulse = ?

Impulse = F x t

F = impulse/t

F = -20000/4s

F = -5000 N

Q11: Solution:

F = ma

a = ?

a = F/m

a = -5000/1000

a = -5m/s^{2}

6 0
3 years ago
A sports car has an average acceleration of 5.81 m/s2. How long does it take for the car to reach 60.0 mi/h, if it starts from r
Aleks04 [339]

Answer:

  4.617 s

Explanation:

The speed of 60 mi/h can be converted to m/s:

  (60 mi/h) × (1609.344 m/mi) × (1 h)/(3600 s) = 26.8244 m/s

The relationship between speed and acceleration is ...

  v = at

  t = v/a = (26.8244 m/s)/(5.81 m/s²) ≈ 4.617 s

It will take the car 4.617 seconds to reach 60 mi/h starting from rest.

5 0
3 years ago
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What do you notice about the way energy is transferred between objects with different masses?
Galina-37 [17]
I notice that the energy how it’s transferred it goes down slowly and the heat waves slowly rise up when conducting air
7 0
3 years ago
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